Help please? And show work?

Isabelle runs a restaurant that offers a children's menu. This past week, 20 children ate at her restaurant, and 8 of them order

kodGreya [7K]

Fraction=8/20 kids ate a grilled cheese at her restaurant in the last week. This simplifies to 2/5. Therefore the probability that a randomly selected child at her restaurant is eating a grilled cheese is 2/5.

8 0

2 years ago

What is the solution to the quadratic equation 8m^2+7m-15=-7 ?

Aleks04 [339]

Make equal to zero
add7 both sides
8m^2+7m-8=0
quadratic fomrula

if you have
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

8m^2+7m-8=0
a=8
b=7
c=-8

x= $\frac{-7+/- \sqrt{7^{2}-4(8)(-8)} }{2(8)}$
x= $\frac{-7+/- \sqrt{49+256} }{16}$
x= $\frac{-7+/- \sqrt{305} }{16}$

x= $\frac{-7+ \sqrt{305} }{16}$ or x= $\frac{-7- \sqrt{305} }{16}$

aprox
x=-1.52902 or 0.654016

4 0

3 years ago

Trina was playing with her new puppy last night. She began to

Nata [24]

Answeep-by-step explanation:

he was 76

jk i am stupid and this is nit the right i just wanted to know how t felt to help someone

4 0

3 years ago

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25 POINTS AND BRAINLIEST PLEASE HELP ASAP

dexar [7]

M is a midpoint of BC so:

$M=\left(\dfrac{\boxed{2}\boxed{a}+a}{\boxed{2}},\dfrac{\boxed{0}+b}{2}\right)=\left(\dfrac{\boxed{3}\boxed{a}}{\boxed{2}},\dfrac{\boxed{b}}{\boxed{2}}\right)$

Length of MA:

$MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=
\sqrt{\left(\dfrac{\boxed{3}a}{\boxed{2}}\right)^2+\left(\dfrac{b}{2}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}$

Length of NB:

$NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\
\sqrt{\left(\dfrac{-3a}{2}\right)^2+\left(\dfrac{b}{\boxed{2}}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}$

5 0

3 years ago

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Which set of parametric equations over the interval 0 ≤ t ≤ 1 defines a line segment with initial point (–5, 3) and terminal poi

Ksivusya [100]

Given:

A line segment with initial point (–5, 3) and terminal point (1, –6).

To find:

The set of parametric equations over the interval 0 ≤ t ≤ 1 which defines the given line segment.

Solution:

Initial point is (–5, 3). So,

$x(0)=-5,y(0)=3$