Answer:
<u>B) Polycystic kidney disease</u>
Explanation:
<u>A) Hypospadias</u>
It is a congenital disease characterized by an abnormal urethral opening on the dorsum of penis.
<u>B) Polycystic kidney disease</u>
It is a disease characterized by the multiple cysts in the kidney as implied by the name.
<u>C) Cystitis</u>
It is defined as the infection of urinary bladder.
<u>D) Dysuria</u>
It is defined as painful urination. It can be due to infection or other underlying disease.
<u>E) Epispadias</u>
It is a congenital disease characterized by an abnormal urethral opening on the ventral surface of penis. It is much less common than hypospadias.
<u>CORRECT ANSWER</u>
From the options, the most appropriate answer is <u>B) Polycystic kidney</u> as it is a disease characterized by the formation of cysts in the kidney. These cysts obstruct urinary flow.
Answer:
All the offsprings will be black-furred (Bb)
Explanation:
This question involves a single gene coding for fur length in rabbits. The allele for black fur (B) is dominant to the allele for white fur (b). This means that a rabbit heterozygous for this gene (Bb) will have a black fur.
According to this question, a purebred black furred male (BB) is bred with a female that had the recessive white fur (bb). The parents will produce gametes as follows:
BB - B only
bb - b only
Using these gametes in a punnet square (see attached image), the genotypic proportion of the produced offsprings is as follows:
Bb, Bb, Bb, Bb
All Bb (heterozygous) means that all of the offsprings will be black-furred.
If the chemical touches another chemical, then there is a higher probability that it's going to react.
The correct answer is True.
I hope this helps you and have a great day!! :)
