2. A car takes 7 hours 50 minute to travel 549 9/10 km.

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

3 0

2.)

average velocity=(change in distance)/(change in time), in this case:

v=(549 9/10)/(7 50/60)

v=(5499/10)/(470/60)

v=(5499/10)(60/470)

v=32994/470

v=70.2 km/hr

...

picture

Make two position functions...

c=15t, and r=120-20(t-1)

c=15t, r=140-20t

They meet when c=r so:

15t=140-20t add 20t to both sides

35t=140 divide both sides by 35

t=4

So they will meet 4 hours after Cindy leaves at 1 pm, thus they meet each other at 5 pm.

check...

c=15(4)=60

r=120-20(4-1)

r=120-20(3)

r=60

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3 years ago

If the distribution is really (5.43,0.54)

defon

Answer:

0.7486 = 74.86% observations would be less than 5.79

Step-by-step explanation:

I suppose there was a small typing mistake, so i am going to use the distribution as N (5.43,0.54)

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The general format of the normal distribution is:

N(mean, standard deviation)

Which means that:

$\mu = 5.43, \sigma = 0.54$