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3 years ago

2. A car takes 7 hours 50 minute to travel 549 9/10 km.

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

3 0

2.)

average velocity=(change in distance)/(change in time), in this case:

v=(549 9/10)/(7 50/60)

v=(5499/10)/(470/60)

v=(5499/10)(60/470)

v=32994/470

v=70.2 km/hr

...

picture

Make two position functions...

c=15t, and r=120-20(t-1)

c=15t, r=140-20t

They meet when c=r so:

15t=140-20t add 20t to both sides

35t=140 divide both sides by 35

t=4

So they will meet 4 hours after Cindy leaves at 1 pm, thus they meet each other at 5 pm.

check...

c=15(4)=60

r=120-20(4-1)

r=120-20(3)

r=60

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James works in a sporting goods store and earns $324 a week and 5% of his sales. One week James earned $432. What were his sales

Bogdan [553]

Answer:

His sales that week were $2,160.

Step-by-step explanation:

First, you have to subtract $324 from the amount he earned that week, to find the 5% he got from sales:

$432-$324=$108

Now, you know that he received $108 that represent 5% of his sales and you can use a rule of three to find the amount that represents 100% which would be his sales that week:

5% → 108

100% → x

x=(100*108)/5=2160

According to this, the answer is that his sales that week were $2,160.

7 0

3 years ago

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times sm

sergey [27]

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel

<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.

We have to prove that the lines are parallel.

If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.

Now, the 1st angle will be 1/6 of right angle is given as:

$\begin{array}{l}{\rightarrow 1^{\text {st }} \text { angle }=\frac{1}{6} \times 90} \\\\ {\rightarrow 1^{\text {st }} \text { angle }=15 \text { degrees }}\end{array}$

And now, 15 degrees is 11 times smaller than the other

Then other angle = 11 times of 15 degrees

$\text {Other angle }=11 \times 15=165 \text { degrees }$

Now, sum of angles = 15 + 165 = 180 degrees.

As we expected their sum is 180 degrees. So the lines are parallel.

Hence, the given lines are parallel

5 0

3 years ago

can you please just help me so that i dont fail this one because everything i've been doing i've been failing and it's because i

Julli [10]

1. r=5
2. x=2
3. x=-3
4. y=11
5. x=-11

6 0

3 years ago

Read 2 more answers

The following equation will have two solutions, y = x2 - 2x - 15?<br> True<br> False

motikmotik

The answer would be False.

3 0

3 years ago

Need help please !!!

blsea [12.9K]

Answer:

option C is the correct answer

Step-by-step explanation:

The trigonometric equation you are using has a general form

y = A* tan w*(x - r)

Where

A is the amplitude of the function

w is the frequency rad/s

r is the phase shift

In your case

A = -2

The frequency is

w = (2*pi)/period

period = pi/4

w = 8

r = -pi/2

y = -2* cos 8*(x + pi/2)

7 0

3 years ago