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3 years ago

Simplify: -3(m – 2) – 7m A. -10m + 6 B. -4m + 6 C. 4m – 6 D. 10m + 6

Mathematics

2 answers:

Sholpan [36]3 years ago

8 0

<h2>Answer:The answer is the letter A</h2>

Masja [62]3 years ago

4 0

The correct answer is A

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A fruit seller has 3 crates of apples. Each crate has 100 apples. If he packed 6 apples in 1 box. Which of these gives the numbe

xz_007 [3.2K]

Answer:

300 divided by 6

Step-by-step explanation:

Given that;

Number of crates of apple owned by fruit seller = 3 crates

Number of apples in each crate = 100 apples

He packed 6 apples in 1 box;

Unknown:

Number of boxes needed to pack all the apples = ?

This problem is pretty straight forward;

Number boxes needed to pack all apples = $\frac{Number of crates owned by fruit seller x number of apples per crate}{Number of apples per box}$

Input the parameters and solve;

Number of boxes need to pack all apples = $\frac{100 x 3}{6}$ = $\frac{300}{6}$

So the solution is 300 divided by 6

5 0

2 years ago

(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

Explanation:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

Step(i):-

Given differential problem

y′+3 y=9 t

Take the Laplace transform of both sides of the differential equation

L( y′+3 y) = L(9 t)

Using Formula Transform of derivatives

L(y¹(t)) = s y⁻(s)-y(0)

By using Laplace transform formula

$L(t) = \frac{1}{S^{2} }$

Step(ii):-

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

Step(iii):-

By using partial fractions , we get

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

B = 9/3 = 3

Put s = -3 in equation(i)

9 = C(-3)²

C = 1

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

0 = A + C

put C=1 , becomes A = -1

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

Step(iv):-

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

By using inverse Laplace transform

$L^{-1} (\frac{1}{s} ) =1$

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

Final answer:-

Now the solution , we get

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

2 years ago

Can you help? I'm just too lazy to answer it lol

Usimov [2.4K]

Answer:

second answer should be corr3ect tell em if wrong

Step-by-step explanation:

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2 years ago

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Ashleigh bought 5 chocolate eggs for $1.00 EACH and a basket for $1.79. How much did she spend?

Ivahew [28]

Answer:

The answer is 6.79 dollars

Step-by-step explanation:

The answer is 6.79 dollars because 5 times 1 (she bought 5 eggs for 1 dollar each) + the added basket 1.79 equals $6.79

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2 years ago

Read 2 more answers

Choose the best term from the box vocabulary 1. An ....------

Alexus [3.1K]

1. expanded form
2. round

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2 years ago