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Anit [1.1K]
3 years ago
6

0.134 bar in the form of p/q​

Mathematics
1 answer:
kenny6666 [7]3 years ago
6 0

Answer:

67/500

Step-by-step explanation:

we have

The decimal number 0.134

Convert to a fraction number

Multiply by (1,000/1,000) the number

0.134*(1,000/1,000)=134/1,000

Simplify

Divide by 2 both numerator and denominator

67/500

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The population of a certain species of oak tree in a national forest declines each year by one-fourth. So, after each year, only
dolphi86 [110]

Answer: 25%

Step-by-step explanation: The question tells us that the population decreases by 1/4 every single year. That means, since 1/4 equals .25, the population decreases by 25% every year :)

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80/3 = 26 2/3

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Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
3 years ago
Systems of equations substitution y=8 y=x+1
klemol [59]
(8) = x +1

same thing as 8 = 1x

divide both sides by 1 and x = 8 Y= 8
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3 years ago
Find what h equals please help ASAP THANK YOU!<br><br> 4h-1=3h+2
Sunny_sXe [5.5K]
H = 3.

FIRST STEP:
<span>Add 1 to both sides to get rid of the -1 on the left side.
4h-1 = 3h+2
</span><span>4h-1 (+1) = 3h+2 (+1)
</span><span>4h = 3h+3
 
SECOND (FINAL) STEP:
Subtract 3h from both sides to get rid of the 3h on the right side.
</span>4h(-3h) = 3h+3 (-3h)
h = 3
Hope this helps, sorry if it's hard to understand :)
3 0
3 years ago
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