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Daniel [21]
3 years ago
5

Please help due tomorrow

Mathematics
2 answers:
alisha [4.7K]3 years ago
8 0
Rope B is 5 feet
Rope A is shorter
Rope A is 1 foot shorter
The total length of Rope A and B is 9 feet

Hope this helps... mark as Brainliest plz
Assoli18 [71]3 years ago
3 0
Rope B is 5 feet and rope A is shorter
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Please help me! I need the anwser asap​
sasho [114]
What is the question you are trying to ask
3 0
3 years ago
Three consecutive numbers are such that when they are taken in increasing order and multiplied by 2,3and 4 respectively, they ad
Ivenika [448]

Answer:

7 , 8 , 9

Step-by-step explanation:

Assume three consecutive number are,

x , (x+1) , (x+2)

Multiplied by 2 ,3 and 4 respectively

2x , 3(x + 1) , 4(x + 2)

Sum of all = 74

So,

2x + 3(x + 1) + 4(x + 2) = 74

2x + 3x + 3 + 4x + 8 = 74

9x + 11 = 74

9x = 63

x = 7

So,

x , (x+1) , (x+2)

7 , (7+1) , (7+2)

7 , 8 , 9

3 0
3 years ago
A penny, a nickel, a dime, and a quarter are tossed. What is the probability of obtaining at least one head on the tosses?
Anton [14]
The penny can land two ways. The nickel can land two ways. The dime can land two ways. The quarter can land two ways. The total number of ways that all of them can land is (2x2x2x2)= 16 possibilities. Only ONE result shows no heads . . . TAIL-TAIL- TAIL-TAIL. All of the other 15 possibilities include at least one HEAD. So the probability is 15/16 = 93.25% .
5 0
3 years ago
11. Keng creates a painting on a rectangular canvas with a width that is four inches longer
GrogVix [38]

Part A

<h3>Answer:  h^2 + 4h</h3>

-------------------

Explanation:

We multiply the length and height to get the area

area = (length)*(height)

area = (h+4)*(h)

area = h(h+4)

area = h^2 + 4h .... apply the distributive property

The units for the area are in square inches.

===========================================================

Part B

<h3>Answer:  h^2 + 16h + 60</h3>

-------------------

Explanation:

If we add a 3 inch frame along the border, then we're adding two copies of 3 inches along the bottom side. The h+4 along the bottom updates to h+4+3+3 = h+10 along the bottom.

Similarly, along the vertical side we'd have the h go to h+3+3 = h+6

The old rectangle that was h by h+4 is now h+6 by h+10

Multiply these expressions to find the area

area = length*width

area = (h+6)(h+10)

area = x(h+10) ..... replace h+6 with x

area = xh + 10x .... distribute

area = h( x ) + 10( x )

area = h( h+6 ) + 10( h+6 ) .... plug in x = h+6

area = h^2+6h + 10h+60 .... distribute again twice more

area = h^2 + 16h + 60

You can also use the box method or the FOIL rule as alternative routes to find the area.

The units for the area are in square inches.

6 0
3 years ago
Use De Moivre’s Theorem to compute the following: <img src="https://tex.z-dn.net/?f=%5B3%28cos27%2Bisin27%29%7D%5E5" id="TexForm
zhannawk [14.2K]
Hello: 
<span>Use De Moivre’s Theorem : 
</span>(3(cos27 +isin27)^5 = 3^5( cos(27 × 5) +isin(27 × 5))
                                = 3^5 ( cos(135)+i sin(135))
                                = 3^5(-√2/2+i √2/2) 
because :  cos(135) = -√2/2    and   sin(135) = √2/2
(3(cos27 +isin27)^5 = (- 3^5√2/2)+ i ( 3^5√2/2)  ...(form : a+ib  when
a= (- 3^5√2/2)  and  b = ( 3^5√2/2)
4 0
3 years ago
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