F(x) = x^2 + 6x + 8
= b^2 - 4ac
= (6)^2 - 4(1)(8)
= 36 - 4(8)
= 36 - 32
= 4
g(x) = x2 + 4x + 8
= b^2 - 4ac
= (4)^2 - 4(1)(8)
= 16 - 4(8)
= 16 - 32
= -16
h(x) = x2 – 12x + 32
= b^2 - 4ac
= (-12)^2 - 4(1)(32)
= 144 - 4(32)
= 144 - 128
= 16
k(x) = x2 + 4x – 1
= (4)^2 - 4(1)(-1)
= 16 - 4(-1)
= 16 + 4
= 20
p(x) = 5x2 + 5x + 4
= b^2 - 4ac
= (5)^2 - 4(5)(4)
= 25 - 4(20)
= 25 - 80
= -55
t(x) = x2 – 2x – 15
= b^2 - 4ac
= (-2)^2 - 4(1)(-15)
= 4 - 4(-15)
= 4 + 60
= 64
Answer:
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Answer:
a.)
Operant conditioning -
It is a type of learning in which a person learns from consequences ( which may be positive or negative ) that follows person's behavior.
The procedures which encourage the person to do the things the same way he/ she used to do are called reinforcement,
The procedures which discourage the person to do the things the same way he/ she used to do are called punishment.
b.)
Strategies Jim and Kelly could use to encourage or discourage Ryan's behaviors :
Positive Reinforcement -
If Ryan eats without dropping off his food from the plate , it will be encouraging for him if Jim and Kelly appreciate him or buy gifts for him.
Negative Reinforcement -
If Ryan eats without dropping off his food from the plate , it will be encouraging for him if Jim and Kelly should avoid that behavior due to which Ryan is not learning the table manners.
For example - The scolding of Jim or Kelly when Ryan's is dropping off the food on the floor.
Positive Punishments -
If Ryan eats with dropping off his food from the plate , it will be encouraging for him if Jim and Kelly will add some consequences which Ryan will hate.
For example - If Ryan is eating with dropping off the food and Jim or Kelly yells at Ryan for his bad behavior.
Negative Punishments -
If Ryan eats with dropping off his food from the plate , it will be discouraging for him if Jim and Kelly removing any good thing in which Ryan is comfortable.
For example - Ryan's watching TV time reduced or taken away his toys.
Replacing <em>F</em> with <em>F</em> + 1 gives
5/9 (<em>F</em> + 1 - 32) = 5/9 (<em>F</em> - 32) + 5/9 = <em>C</em> + 5/9
so a temperature increase of 1º F translates to a 5/9º increase in Celsius, so I is true.
Replacing <em>F</em> with <em>F</em> + 5/9 gives
5/9 (<em>F</em> + 5/9 - 32) = 5/9 (<em>F</em> - 32) + (5/9)² = <em>C</em> + 25/81
so increasing the temperature by 5/9º F amounts to a 25/81º increase in Celsius, so III is false.
Solve for <em>F</em> in terms of <em>C</em> :
<em>F</em> = 9/5 <em>C</em> + 32
Replacing <em>C</em> with <em>C</em> + 1 gives
9/5 (<em>C</em> + 1) + 32 = 9/5 <em>C</em> + 32 + 9/5 = <em>F</em> + 9/5
and 9/5 = 1.8, so a 1º C increase translates to a 1.8º F increase, so II is also true and the answer is D.
