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Goryan [66]
4 years ago
7

Mention 4applications of thermal expansion​

Physics
2 answers:
katovenus [111]4 years ago
6 0

Answer:

  • thermometers
  • combustion engines
  • fitting or loosening of metallic parts
  • providing lift for hot-air balloons

Explanation:

The thermal expansion properties of liquids and metals are used in thermometers of many types. The liquid in a bulb thermometer expands to provide indication on a calibrated scale. Thermal expansion of a metal coil is used in dial thermometers and in thermostats of many kinds.

The thermal expansion of hot gas drives the cylinders or turbines in combustion engines, jet engines, and thermal cycle motors.

Thermal expansion of metal relative to glass can help remove a stuck jar lid. Similarly, machine parts can be expanded by heating to facilitate assembly or disassembly.

The expansion of warmer air in the atmosphere gives rise to updrafts and thermals that can be used by birds and bugs and people for gaining altitude. The expansion of air in the envelope of a hot-air balloon drives its lift as well.

ra1l [238]4 years ago
3 0

thermak expansion is for cocluding the elctric value of solar panels

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Why didn't the astronauts land on the moon 3.17 answers punchline?
Vinvika [58]

Answer : Answers to this 3.17 punchline had many opinions from many people, some said that it was a "full" moon day so the astronauts didn't landed on it.

While some said that the astronauts took off during the day time when there is no moon seen, whereas there were some other people who said that astro means star not satellite so they didn't landed.

There were answers like, astro naut sounds similar to naught which means zero (0) so this may also be the reason that they didn't landed.

3 0
3 years ago
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5 milligrams into quintal​
Greeley [361]

Answer:

divide the mass value by 1e+8

4 0
3 years ago
A mass free to vibrate on a level, frictionless surface at the end of a horizontal spring is pulled 35 cm from its equilibrium p
saul85 [17]

Answer:

0.67 s

Explanation:

This is a simple harmonic motion (SHM).

The displacement, x, of an SHM is given by

x = A\cos(\omega t)

A is the amplitude and \omega is the angular frequency.

We could use a sine function, in which case we will include a phase angle, to indicate that the oscillation began from a non-equilibrium point. We are using the cosine function for this particular case because the oscillation began from an extreme end, which is one-quarter of a single oscillation, when measured from the equilibrium point. One-quarter of an oscillation corresponds to a phase angle of 90° or \frac{\pi}{4} radian.

From trigonometry, \sin A =\cos B if A and B are complementary.

At t = 0, x = 3.5

3.5 = A\cos(\omega \times0)

A =3.5

So

x = 3.5\cos(\omega t)

At t = 0.12, x = 1.5

1.5 = 3.5\cos(0.12\omega)

\cos(0.12\omega)=\dfrac{1.5}{3.5}=0.4286

0.12\omega =\cos^{-1}0.4286

0.12\omega = 1.13

\omega = 9.4

The period, T, is related to \omega by

T = \dfrac{2\pi}{\omega} = \dfrac{2\times3.14}{9.4}=0.67

5 0
3 years ago
Please answer all of these questions for brainly!
Nana76 [90]
Answer:

1. C
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3 0
3 years ago
Simpson drives his car with an average velocity of 48.0 km/h to the east. How long will it take him to drive 144 km on a straigh
Lorico [155]

Answer:

The time save by Simpson is 25.8 minutes.

Explanation:

Given that,

Velocity of the car, v = 48 km/h

Distance covered by the car, d = 144 km

Let t is the time taken by the car. Speed of an object is given by distance covered per unit time. It is given by :

v=\dfrac{d}{t}

t=\dfrac{d}{v}

t=\dfrac{144\ km}{48\ km/h}

t = 3 hours

If the velocity is increased to 56 km/h to the east. Time taken is given by :

t'=\dfrac{144\ km}{56\ km/h}

t' = 2.57 seconds

The time save by Simpson increasing his average velocity is given by :

\Delta t=t-t'

\Delta t=3-2.57

\Delta t=0.43\ hours

or

\Delta t=25.8\ min

So, the time save by Simpson is 25.8 minutes. Hence, this is the required solution.                                                        

5 0
4 years ago
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