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3 years ago

(Science)

Physics

2 answers:

FromTheMoon [43]3 years ago

7 0

Answer:

kinetic energy

Explanation:

because it is at the top going down

jek_recluse [69]3 years ago

5 0

Answer:

its d which is gravity

Explanation:

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6.7.1 Current and Current Density A sphere of radius 10 mm that carries a charge of 8 nC =8x 10°C is whirled in a circle at the

aev [14]

Answer:

Part a)

Rate of charge flow is known as electric current

Part b)

Average current flow is

$i = 4\times 10^{-7} A$

Part c)

As we know that current density is current per unit area

$j = 1.27 \times 10^{-3} A/m^2$

Explanation:

As we know that angular frequency of rotation is

$\omega = 100\pi rad/s$

now by basic definition of electric current

Part a)

Rate of charge flow is known as electric current

$i = \frac{dq}{dt}$

so here we have

$i = \frac{Q}{T}$

$i = Qf$

Part b)

here we know that

$\omega = 2\pi f$

$100\pi = 2\pi f$

$f = 50 Hz$

now we have

$i = (8\times 10^{-9})(50)$

$i = 4\times 10^{-7} A$

Part c)

As we know that current density is current per unit area

So we have

$j = \frac{i}{A}$

$j = \frac{4\times 10^{-7}}{\pi(10\times 10^{-3})^2}$

$j = 1.27 \times 10^{-3} A/m^2$

6 0

3 years ago

Dominic made the table below to organize his notes about mixtures. What mistake did Dominic make? The title should read “Propert

Alex17521 [72]

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3 years ago

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A basketball of mass 0.23kg is thrown horizontally against a rigid vertical wall with a velocity of 20m/s. It rebounds with a ve

Anna11 [10]

Answer:

$8.1\:\mathrm{Ns}$

Explanation:

The impulse-momentum theorem gives the impulse on an object to be equal to the change in momentum of that object. Since mass is maintained, the change in momentum of the basketball is:

$\Delta p = m\Delta v$ , where $m$ is the mass of the basketball and $\Delta v$ is the change in velocity.

Since the basketball is changing direction, its total change in velocity is:

$\Delta v = 20-(-15)=35\:\mathrm{m/s}$ .

Therefore, the basketball's change in momentum is:

$\Delta p = m\Delta v = 0.23\cdot 35= 8.05=8.1\:\mathrm{kg\cdot m/s}$ .

Thus, the impulse on the basketball is $\fbox{$8.1\:\mathrm{Ns}$}$ (two significant figures).

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2 years ago

Is a bike standing still potential or kinetic?

BartSMP [9]

Answer:

potential

Explanation:

Potential energy is stored

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erma4kov [3.2K]

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3 years ago