75 x 0.72 is the answer, you can type it into a calculator
From the given tabular data,
Volume of water (V) = 50.0 ml
Mass of water (m) = 49.7 g
So, the density of water (ρ) = Mass / Volume
or, = 49.7 g /50.0 ml = 0.994 g / ml
<u>Actual value of the density of water (ρ') = 0.998 g /ml</u>
So, the percentage error in the density of water
= [( actual value - observed value) / actual value ] ×100
or, = [ (0.998 g /ml - 0.994 g / ml ) / 0.998 g /ml ] ×100
or, = 0.4 %
Hence, the required % error in the density of water will 0.4 %.
Answer: I’m pretty sure it’s SAA
Step-by-step explanation: if it were ASA the side would be in between the two congruent Angles but that’s not the case here. And it has enough information so it’s also not neither.
First you would want to find the length of one eraser and then multiply that by 2. To find the length of one you take the total length or all of them and divide it my the total number of them. 29 1/4 is 117/4.
(117/4) / 13 Dividing by something is the same as multiplying by the opposite.
117/4 × 1/13 = 117/52
Now you multiply by 2.
117/52 * 2/1 Cross simplify
117/26 * 1/1
117/26 inches or 4 1/2 inches.
