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aliya0001 [1]
3 years ago
14

Which statement about the functions is true?

Mathematics
1 answer:
Leno4ka [110]3 years ago
6 0

Answer:

D i think

ok the fx are common

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The measure of angle 1 is 27 degrees.<br> Complement:<br> Supplement:
Paladinen [302]

Answer:

Complement: 63°

Supplement: 153°

Step-by-step explanation:

NOTE: Supplementary angles are two angles that have a sum of 180°. Complementary angles are two angles that have a sum of 90°.

<u><em>Please mark as brainliest if answer is right </em></u>

Have a great day, be safe and healthy  

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3 0
3 years ago
Melanie has a piece of cloth 12 and 1/3 yards long. How many 3/4 yard-long pieces can be cut from the cloth?
Harrizon [31]
This is a division problem. First, get 12 1/3 into fraction form instead of mixed number form to make your life easier;  
12  \frac{1}{3} =  \frac{36}{3} +  \frac{1}{3} =  \frac{37}{3}  &#10;  
Now, divide the two fractions. Since this is fraction division, the reciprocal is flipped and the two fractions multiplied.  
\frac{37}{3} *  \frac{4}{3} =  \frac{148}{9} = 16  \frac{4}{9}  &#10;  
The answer from the fraction division is 16 and four-ninths, but because you need a whole number as an answer,  
the answer is 16 pieces.
8 0
3 years ago
Read 2 more answers
I marked all 3 parts. I need to know part C (the shaded part). anybody mind helping?​
Mnenie [13.5K]

Answer:

Area of shaded part ABCEF = 66 sq.cm

Step-by-step explanation:

AB = 8cm

CD = 8cm

Let DE = x cm

CE = 3x cm

CD =  CE + DE = 8cm

        x + 3x = 8

4x = 8

x = 8/4 = 2 cm

DE = 2cm

CE = 3 * 2 = 6 cm

Area of triangle ADE = 1/2 * base * height

                                   = 1/2 * DE * AD

                                    = 1/2 * 2 * 11 = 11 sq. cm

Area of triangle AEF = Area of triangle ADE = 11 sq. cm

Area of Rectangle ABCD =  l * b = 8 * 11 = 88 sq.cm

Area of shaded part ABCEF =  Area of Rectangle ABCD - (Area of triangle AEF + Area of triangle ADE)

    = 88 - ( 11 + 11 )  = 88 -22 = 66 sq.cm

6 0
3 years ago
Explain how to determine if you have a direct variation or proportional relationship
neonofarm [45]

Answer:

straight line that passes through the origin

Step-by-step explanation:

Two variables are said to have a direct variation or proportional relationship if it can be represented by y = kx, where k is a constant.

Comparing this with the equation of a straight line y = mx + b, where m is the slope of the line and b is the y intercept (value of y when x = 0), We can tell if the say that the graph of a direct variation or proportional relationship is a straight line with no y intercept (b = 0, that is it passes through the origin).

8 0
3 years ago
If g(x) = |2x-9|, find g(2)+g(3)
Semenov [28]
X=5 , x=3 - just plug in 2 and 3 into x and the lines will make it positive instead of negative
5 0
2 years ago
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