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3 years ago

An oscillator makes 360 vibrations in 3 minutes.

Physics

2 answers:

IceJOKER [234]3 years ago

8 0

Explanation :

It is given that an oscillator makes 360 oscillations in 3 minutes.

(a) Using unitary method :

No. of vibrations in one minute is, $n=\dfrac{360}{3}=120$

So, no of vibrations in one minute is 120.

(b) Similarly,

3 minutes = 180 seconds

No of vibrations in one second is $\dfrac{360}{180}=2$

So, the no of vibrations in one second is 2.

(c) Time period of the wave is given by :

$T=\dfrac{1}{2\ s^{-1}}$

$T=0.5\ s$

The time period of the wave is 0.5 s

(d) The no of vibation per second is called as its frequency.

$\nu=\dfrac{1}{T}$

$\nu=2\ Hz$

Hence, this is the required solution.

Pie3 years ago

3 0

A) 120 vibrations per minute
b)d) 2 Hz (vibrations per second)
c) The period is half of the second.

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A mango falls fromthe top its tree passing a window which is 2.4m tall by taking 0.4s

Natasha2012 [34]

Explanation:

There are three points in time we need to consider. At point 0, the mango begins to fall from the tree. At point 1, the mango reaches the top of the window. At point 2, the mango reaches the bottom of the window.

We are given the following information:

y₁ = 3 m

y₂ = 3 m − 2.4 m = 0.6 m

t₂ − t₁ = 0.4 s

a = -9.8 m/s²

t₀ = 0 s

v₀ = 0 m/s

We need to find y₀.

Use a constant acceleration equation:

y = y₀ + v₀ t + ½ at²

Evaluated at point 1:

3 = y₀ + (0) t₁ + ½ (-9.8) t₁²

3 = y₀ − 4.9 t₁²

Evaluated at point 2:

0.6 = y₀ + (0) t₂ + ½ (-9.8) t₂²

0.6 = y₀ − 4.9 t₂²

Solve for y₀ in the first equation and substitute into the second:

y₀ = 3 + 4.9 t₁²

0.6 = (3 + 4.9 t₁²) − 4.9 t₂²

0 = 2.4 + 4.9 (t₁² − t₂²)

We know t₂ = t₁ + 0.4:

0 = 2.4 + 4.9 (t₁² − (t₁ + 0.4)²)

0 = 2.4 + 4.9 (t₁² − (t₁² + 0.8 t₁ + 0.16))

0 = 2.4 + 4.9 (t₁² − t₁² − 0.8 t₁ − 0.16)

0 = 2.4 + 4.9 (-0.8 t₁ − 0.16)

0 = 2.4 − 3.92 t₁ − 0.784

0 = 1.616 − 3.92 t₁

t₁ = 0.412

Now we can plug this into the original equation and find y₀:

3 = y₀ − 4.9 t₁²

3 = y₀ − 4.9 (0.412)²

3 = y₀ − 0.83

y₀ = 3.83

Rounded to two significant figures, the height of the tree is 3.8 meters.

6 0

3 years ago

Part of being a good team worker is

andrey2020 [161]

Team work and a can do attitude is very important when being a team worker, as well as being open minded!
I hope this helps!

6 0

3 years ago

Read 2 more answers

Calculate the potential energy of a rock that has a 45 kg mass and is sitting

Montano1993 [528]

Answer:

P.E = 13230 J

Explanation:

Given,

The mass of the rock, m = 45 Kg

The rock is sitting at a height from the ground, h = 30 m

The acceleration due to gravity, g = 9.8 m/s²

The potential energy of the body is given by the formula,

P.E = mgh joules

Substituting the given values in the above equation

P.E = 45 x 9.8 x 30

= 13230 J

Hence, the potential energy of the rock is P.E = 13230 J

6 0

3 years ago

Your car is initially at rest when your hit that gas and the car begins to accelerate at a rate of 1.464 m/s/s. The acceleration

tamaranim1 [39]

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Explanation:

6 0

3 years ago

A shaving or makeup mirror is designed to magnify your face by a factor of 1.40 when your face is placed 20.0cm in front of it

Dennis_Churaev [7]

Answer:

(a) convex mirror

(b) virtual and magnified

Explanation:

The having mirror is convex mirror.

distance of object, u = - 20 cm

magnification, m = 1.4

(a) As the image is magnified and virtual , so the mirror is convex in nature.

(b) The image is virtual and magnified.

Use the formula of magnification.

$m =-\frac{v}{u}\\1.4=-\frac{v}{-20}\\v =28 cm$

Use the mirror equation, let the focal length is f.

$\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\\frac{1}{f}=\frac{1}{28}+\frac{1}{20}\\\frac{1}{f}=\frac{28+20}{560}\\f=11.67cm$

Radius of curvature, R = 2 f = 2 x 11.67 = 23.3 cm

5 0

3 years ago