Question

An oscillator makes 360 vibrations in 3 minutes.

Answer 1

Explanation :

It is given that an oscillator makes 360 oscillations in 3 minutes.

(a) Using unitary method :

No. of vibrations in one minute is, $n=\dfrac{360}{3}=120$

So, no of vibrations in one minute is 120.

(b) Similarly,

3 minutes = 180 seconds

No of vibrations in one second is $\dfrac{360}{180}=2$

So, the no of vibrations in one second is 2.

(c) Time period of the wave is given by :

$T=\dfrac{1}{2\ s^{-1}}$

$T=0.5\ s$

The time period of the wave is 0.5 s

(d) The no of vibation per second is called as its frequency.

$\nu=\dfrac{1}{T}$

$\nu=2\ Hz$

Hence, this is the required solution.

Answer 2

A) 120 vibrations per minute
b)d) 2 Hz (vibrations per second)
c) The period is half of the second.