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NeTakaya
2 years ago
10

James makes a treasure map to locate a secret item on McEachern Campus. He uses the

Physics
2 answers:
barxatty [35]2 years ago
4 0

Answer:

Its a

Explanation:

Inessa [10]2 years ago
3 0

Answer:

south

Explanation:

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The battery provides electrical energy to run an electric circuit.
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a toy propeller fan with a moment of inertia of .034 kg x m^2 has a net torque of .11Nxm applied to it. what angular acceleratio
Harman [31]

Answer:

The  angular acceleration is  \alpha  = 3.235 \ rad/s ^2

Explanation:

From the question we are told that

    The moment of inertia is  I  =  0.034\ kg \cdot m^2

     The  net torque is  \tau  =  0.11\ N \cdot m

Generally the net torque is mathematically represented as

           \tau =  I  *  \alpha

Where \alpha is the angular acceleration so  

        \alpha  =  \frac{\tau }{I}

substituting values

         \alpha  =  \frac{0.1 1}{ 0.034}

        \alpha  = 3.235 \ rad/s ^2

6 0
3 years ago
A car of mass m accelerates from rest along a level straight track, not at constant acceleration but with constant engine power,
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2 years ago
The first four steps in the formation of the sun are listed below.
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(B)Option b is your answer..........
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3 years ago
Read 2 more answers
A tuning fork generates sound waves with a frequency of 240 Hz. The waves travel in opposite directions along a hallway, are ref
Bingel [31]

Answer:

The phase difference between the reflected waves when they meet at the tuning fork is 159.29 rad.

Explanation:

Given that,

Frequency of sound wave = 240 Hz

Distance = 46.0 m

Distance of fork = 14 .0 m

We need to calculate the path difference

Using formula of path difference

\Delta x=2(L_{2}-L_{1})

Put the value into the formula

\Delta x =2((46.0-14.0)-14.0)

\Delta x=36\ m

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{v}{f}

Put the value into the formula

\lambda=\dfrac{343}{240}

\lambda=1.42\ m

We need to calculate the phase difference

Using formula of the phase difference

\phi=\dfrac{2\pi}{\lambda}\times \delta x

Put the value into the formula

\phi=\dfrac{2\pi}{1.42}\times36

\phi=159.29\ rad

\phi\approx 68.2^{\circ}

Hence, The phase difference between the reflected waves when they meet at the tuning fork is 159.29 rad.

7 0
3 years ago
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