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NeTakaya
3 years ago
10

James makes a treasure map to locate a secret item on McEachern Campus. He uses the

Physics
2 answers:
barxatty [35]3 years ago
4 0

Answer:

Its a

Explanation:

Inessa [10]3 years ago
3 0

Answer:

south

Explanation:

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Which of the following in the list is the best conductor: plastic, metal, styrofoam, or glass?
tensa zangetsu [6.8K]

Answer:

Metal

Explanation:

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A 142 kg boulder is located near the edge of a cliff 25 m above the ground. What is the gravitational potential energy of the bo
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PE = mass * height * 9.81
PE = 142 * 25 * 9.81
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A certain plucked string produces a fundamental frequency of 150 hz. Which frequency is not one of the harmonics produced by tha
Irina-Kira [14]

Answer:

Some of the frequency that cannot be produced by the string includes 400Hz, 500Hz 650Hz etc...

Explanation:

Harmonics in strings are defined as the integral multiples of its fundamental frequency. This multiples are in arithmetic progression.

For example if Fo is the fundamental frequency of the string, the harmonics will be 2fo, 3fo, 4fo, 5fo... etc

If the string produces a fundamental frequency of 150Hz, some of the harmonics produced by the string will be 300Hz, 450Hz, 600Hz, 750Hz... etc

Some of the harmonics that cannot be produced include 400Hz, 500Hz 650Hz etc...

6 0
4 years ago
A firewoman dropped a person onto the safety net. Right before the person hit the net he had a
sergejj [24]

Answer:

The Mass of a person is calculated to be 28.6kg .

Explanation:

This is based on Kinetic energy and we know, that Kinetic energy is the energy possessed by body by virtue of its motion .

It can be calculated by expression :

K.E=1/2mv²

Velocity of a person = 11.2m/sec

Kinetic energy = 1800J

Mass of person = ?

We know ,

K.E=1/2mv²

so, putting values we have :

1800=1/2 x m x (11.2)²

That is ,

m=1800 x 2 /11.2 x 11.2

or

m=3600/125.44

m = 28.6 kg

6 0
3 years ago
A bowling ball of mass m = 1.7 kg drops from a height h = 14.2 m. A semi-circular tube of radius r = 6.2 m rest centered on a sc
marshall27 [118]

Answer:

W_net = mg + 2mgh/r

Explanation:

The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.

Now, gravitational force is; F_g = mg

While centripetal force is; F_c = mv²/r

Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.

Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.

Thus;

F_c = 2mgh/r

Where;

m is ball mass

r is tube radius

h is fall height

Thus, the net force will be;

F_net = F_g + F_c

Now, Net force would be equal to the net weight that will be read on the scale.

Thus;

W_net = F_net = F_g + F_c

W_net = mg + 2mgh/r

8 0
3 years ago
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