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makvit [3.9K]
3 years ago
9

An circuit has a section AB as shown in the fig. with E= 10V. (sf C_1) = 1.0 F, (sf C_2) = 2.0 F and the potential difference (s

f V_a-V_b = 5V). The voltage across (sf C_1) is?
Physics
1 answer:
bagirrra123 [75]3 years ago
4 0

Without the fig, we know nothing about  AB,  C_1,  C_2,  V_a, or  V_b.
The probability of getting any kind of answer from anybody who hasn't
seen or tasted the fig is vanishingly small.

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If a car used 260.000 W of power to complete a race in 15 s. how much work did the car do?
marta [7]

Work done by the car is 3900 J

Explanation:

  • Power and work are related by the equation, Power = Work Done/Time
  • Power is the rate at which work is done.
  • Here, the car uses power of 260 W and time taken is 15 s.

Work Done = Power × Time

                   = 260 × 15 = 3900 J

3 0
4 years ago
A flashlight contains a battery of two cells in series, with a bulb of resistance 12 Ohms. The internal resistance of each cell
Elina [12.6K]

Answer:

1.5024

Explanation:

Draw a diagram. Put the two cells in series. Now draw 3 resistors. Two of them equal 0.26 ohms each. The third one is the lightbulb which is 12 ohms.

R = 0.26 + 0.26 + 12 = 12.52

The bulb has a voltage of 2.88 volts across it. You can get the current from that.

i = E / R

i = 2.88 / 12 =

i = 0.24 amps.

Now you can get the voltage drop across the two cells.

E = ?

R = 0.26

i = 0.24 amps

E = 0.26 * 0.24

E = 0. 0624

Finally divide the 2.88 by 2 to get 1.44

Each cell has an emf of 1.44 + 0.0624 = 1.5024

4 0
3 years ago
Before the positive psychology movement, psychology focused mainly on
KonstantinChe [14]
Before positive psychology, the main focus was mostly pathology, that is, studying various psychological issues and sometimes finding ways to treat them, or sometimes not and just studying them for the sake of studying them and noting their occurrence.
7 0
3 years ago
Read 2 more answers
If you stood on a planet having a mass four times higher than Earth's mass, and a radius two times 70) lon longer than Earth's r
BigorU [14]

CHECK COMPLETE QUESTION BELOW

you stood on a planet having a mass four times that of earth mass and a radius two times of earth radius , you would weigh?

A) four times more than you do on Earth.

B) two times less than you do on Earth.

C) the same as you do on Earth

D) two times more than you do on Earth

Answer:

OPTION C is correct

The same as you do on Earth

Explanation :

According to law of gravitation :

F=GMm/R^2......(a)

F= mg.....(b)

M= mass of earth

m = mass of the person

R = radius of the earth

From law of motion

Put equation b into equation a

mg=GMm/R^2

g=GMm/R^2

g=GM/R^2

We know from question a planet having a mass four times that of earth mass and a radius two times of earth radius if we substitute we have

m= 4M

r=(2R)^2=4R^2

g= G4M/4R^2

Then, 4in the denominator will cancel out the numerator we have

g= GM/R^2

Therefore, g remain the same

7 0
3 years ago
A linear accelerator uses alternating electric fields to accelerate electrons to close to the speed of light. A small number of
kobusy [5.1K]

Answer:

8.1 x 10^13 electrons passed through the accelerator over 1.8 hours.

Explanation:

The total charge accumulated in 1.8 hours will be:

Total Charge = I x t = (-2.0 nC/s)(1.8 hrs)(3600 s/ 1 hr)

Total Charge = - 12960 nC = - 12.96 x 10^(-6) C

Since, the charge on one electron is e = - 1.6 x 10^(-19) C

Therefore, no. of electrons will be:

No. of electrons = Total Charge/Charge on one electron

No. of electrons = [- 12.96 x 10^(-6) C]/[- 1.6 x 10^(-19) C]

<u>No. of electrons = 8.1 x 10^13 electrons</u>

6 0
3 years ago
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