An circuit has a section AB as shown in the fig. with E= 10V. (sf C_1) = 1.0 F, (sf C_2) = 2.0 F and the potential difference (s
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The frequency of the human ear canal is 2.92 kHz.
Explanation:
As the ear canal is like a tube with open at one end, the wavelength of sound passing through this tube will propagate 4 times its length of the tube. So wavelength of the sound wave will be equal to four times the length of the tube. Then the frequency can be easily determined by finding the ratio of velocity of sound to wavelength. As the velocity of sound is given as 339 m/s, then the wavelength of the sound wave propagating through the ear canal is
Wavelength=4*Length of the ear canal
As length of the ear canal is given as 2.9 cm, it should be converted into meter as follows:
Then the frequency is determined as
f=c/λ=339/0.116=2922 Hz=2.92 kHz.
So, the frequency of the human ear canal is 2.92 kHz.
The amount of heat needed to increase the temperature of a substance by 
is given by
where m is the mass of the substance, Cs is its specific heat capacity and is the increase of temperature.
If we re-arrange the formula, we get
And if we plug the data of the problem into the equation, we can find the specific heat capacity of the substance:
where m is the mass of the substance, Cs is its specific heat capacity and
If we re-arrange the formula, we get
And if we plug the data of the problem into the equation, we can find the specific heat capacity of the substance: