Answer:
Don't stress your self out. Take your time and read over notes, write down things you think are important.
To find the equation of a line that is parallel to your original equation and goes through a certain point on a graph, here's what you need to know:
First you need to find the slope of your original equation.
To do that, you need to convert it to slope intercept form (y = mx+b).
Add the x over, and then divide everything by 5 to get the y by itself.
Here's what that would look like (without the small steps that I mentioned):
-x + 5y = 25
5y = x + 25
y = 1/5x + 5
That's the original equation rewritten in slope intercept form.
The m represents the slope, so this equation's slope is 1/5.
Because you are given a point, and now you have a slope, the best and easiest route is using point slope form.
I've seen different versions of the equation base but I prefer y - y(sub1) = m(x - x(sub1))
But since I can't use subscripts in this, I'll use the one with h and k. The h is the x value of the point, and the k is the y value.
(h,k)
Then just substitute the values in and solve for y.
y - k = m(x - h)
y + 5 = 1/5(x + 5)
y + 5 = 1/5x + 1
y = 1/5x - 4
Your final answer is
y = 1/5x - 4
You can double check by using a graph. If the slopes are the same, the lines should be parallel.
I hope that helps. If anything didn't make sense, feel free to ask me.
That would be 1/2 r^2 theta where r = radius and theta = angle in radians sp her we have
Area of sector = 1/2 * 4^2 * 2.4 = 8 * 2.4 = 19.2 m^2 Answer
Answer:10 - Saturday Sunday
Step-by-step explanation:
Answer:
-17x+0.8y
Step-by-step explanation:
-8x+7.1y-(9x+6.3y)- you multiply the terms inside with the -1 (it's shown as a ------ minus by most people)
-8x +7.1y -9x -6.3y
-8x -9x +7.1y -6.3y
-17x +0.8y
