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scZoUnD [109]
3 years ago
5

12. What value of c would make x = 4 in the equation 5 + cx = 13 ?

Mathematics
1 answer:
Pavel [41]3 years ago
4 0
Plug in 4 for x and solve equation like so. c=2

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Laura went to a golf shop that has a golf simulator. The simulator estimates the distance that each ball she hits would have gon
Alex_Xolod [135]

Answer:

I can only help you with Part C and E as these two are the ones I am able to answer.

Part C: slopes are not the same

Part E:  195 yards

Step-by-step explanation:

Part C:

Part E: The slope of the line follows a linear pattern; therefore, find the equation for the line by calculating the slope and plugging in a point.

Slope:

y2-y1/x2-x1; (9, 105) (8,115)

(115-105)/(8-9) = -10; the slope is -10, now solve for the equation of the line.

y=mx+b; plug in the point (9,105)

105 = -10(9) +b

105 = -90 +b, add 90 to both sides

195 = b; rewrite the equation;

y=-10x+195; x stands for the iron, plug in 0 for x;

y=-10(0)+195

y=195 yards.

7 0
3 years ago
Find the nonpermissible replacement for s in this expression s-1/s-5​
Mrrafil [7]

Answer: s^2-5s-1/s

Step-by-step explanation: Simplify the expression.

Hope this helps you out! ☺

6 0
3 years ago
618 runners registered for the marathon. Of these runners 0.8% completed the race in under 2 hr 15 min. a) how many runners comp
umka21 [38]

Answer:

Exact = 4.944 Rounded = about 5 Reality = 4 since there can’t be 99.4% of an human.

Step-by-step explanation:

0.8/100 = x/618

618(0.8) = 100x

494.4 = 100x

/100. /100

x = 4.944

7 0
3 years ago
Can someone help pleeeeeeease!!!
Leviafan [203]

Answer:

Yes, with what? The Picture wont show for me.

Step-by-step explanation:

7 0
2 years ago
A red balloon starts at 7.3 meters off the ground and rises at 2.6 meters per second. A blue balloon starts at 12.4 meters off t
nexus9112 [7]
This problem is an example of solving equations with variables on both sides. To solve, we must first set up an equation for both the red balloon and the blue balloon. 

Since the red balloon rises at 2.6 meters per second, we can represent this part of the equation as 2.6s. The balloon is already 7.3 meters off of the ground, so we just add the 7.3 to the 2.6s: 

2.6s + 7.3

Since the blue balloon rises at 1.5 meters per second, we can represent this part of the equation as 1.5s. The balloon is already 12.4 meters off of the ground, so we just add the 12.4 to the 1.5:

1.5s + 12.4

To determine when both balloons are at the same height, we set the two equations equal to each other: 

2.6s + 7.3 = 1.5s + 12.4

Then, we solve for s. First, the variables must be on the same side of the equation. We can do this by subtracting 1.5s from both sides of the equation: 

1.1s + 7.3 = 12.4

Next, we must get s by itself. We work towards this by subtracting 7.3 from both sides of the equation: 

1.1s = 5.1

Last, we divide both sides by 1.1. So s = 4.63. 

This means that it will take 4.63 seconds for both balloons to reach the same height. If we want to know what height that is, we simply plug the 4.63 back into each equation: 

2.6s + 7.3
= 2.6 (4.63) + 7.3
= 19.33

1.5s + 12.4
= 1.5 (4.63) + 12.4
= 19.33

After 4.63 seconds, the balloons will have reached the same height: 19.33 meters.
6 0
3 years ago
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