Answer
Find out the number of hours when the cost of parking at both garages will be the same.
To prove
As given
There are two parking garages in beacon falls .
As given
Let us assume that the y is representing the cost of parking at both garages will be the same.
The total number of hours is represented by the x.
First case
Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .
As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)
Than the equation becomes
y = 3.00 (x -2) + 7.00
written in the simple form
y = 3x - 6 +7
y = 3x + 1
Second case
Garage b charges $3.25 per hour to park.
than the equation becomes
y = 3.25x
Compare both the equations
3x +1 = 3.25x
3.25x -3x = 1
.25x = 1

x = 4hours
Therefore in the 4 hours the cost of parking at both garages will be the same.
Answer:
2.81
Step-by-step explanation:
.81 has a bar over it.
8x10 = 80
4x4 = 16
2x4 divided 2 = 4
80+16+ 4 = 100
Answer:
m∠YWZ=36°
Step-by-step explanation:
Opposite rays are two rays that both start from a common point and go off in exactly opposite directions. Because of this the two rays (WX and WZ) form a single straight line through the common endpoint W.
If rays WX and WZ are opposite, then angle XWZ is straight angle. A straight angle always has the measure of 180°.
Point Y is in the interior of ∠XWZ, then angles XWY and EWZ are supplementary angles (together form straight angle XWZ). Supplementary angles always add up to 180°, then
m∠XWY+m∠YWZ=180°
You are given that
m∠XWY=4(m∠YWZ).
Substitute it into the previous equality:
4(m∠YWZ)+m\angle YWZ=180°
5(m∠YWZ)=180°
m∠YWZ=36°