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Tanzania [10]
3 years ago
8

What is the volume of a cylinder with a hight of 9 cm and a diameter of 6

Mathematics
2 answers:
USPshnik [31]3 years ago
5 0
Our answer is <span>254.47 bacause of the formula for volume of a cylinder  v=pi r^2h</span>
natali 33 [55]3 years ago
3 0
The volume of the cylinder with a hight of 9 cm and a dismeter of 6 is 254.5 cm^3
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Sarah Smart purchased a renewable health club membership for $385 per year. She visited the club twice a month for two years. Wh
Marrrta [24]
Because $385 for two years is 385+385=770
Twice a month for two years=24x2=48
So 770/48=$16.04

Final answer $16.04

5 0
3 years ago
A garage sells 12 different models of a car in 9 different colours.
fomenos

Answer:

108

Step-by-step explanation:

12 x 9 =108

7 0
3 years ago
Read 2 more answers
Composition of functions Find g (f(x)) for the following problems
beks73 [17]

1.

f(x)=-3x\qquad g(x)=5x-6\\\\g(f(x))=5(-3x)-6=\boxed{-15x-6}

2.

f(x)=x-6\qquad g(x)=x^2+6x-2\\\\g(f(x))=(x-6)^2+6(x-6)-2=x^2-12x+36+6x-36-2=\\\\=\boxed{x^2-6x-2}

3.

f(x)=4x+3\qquad g(x)=2x^2-x+1\\\\g(f(x))=2(4x+3)^2-(4x+3)+1=2(16x^2+24x+9)-4x-3+1=\\\\=32x^2+48x+18-4x-3+1=\boxed{32x^2+44x+16}

4.

f(x)=2x^2\qquad g(x)=8x^2+3x\\\\g(f(x))=8(2x^2)^2+3(2x^2)=8\cdot4x^4+6x^2=\boxed{32x^4+6x^2}

7 0
3 years ago
An identification code is to consist of 2 letters followed by 3 digits. how many different codes are possible if repetition is p
Vedmedyk [2.9K]
I like the 'question mark' at the end:

26 letters (English), 10 digits (0,1,...9)

26*26*10*10*10 = 676000

Now, this was for LLDDD (Letter Letter Digit Digit Digit)

It seems this is the order they want. Other wise, one should multiply by all the combinations in the order: LDLDD, DLLDD, etc ... (10 combinations), but again it seems they want this LLDDD

So 676000



5 0
3 years ago
Please help! i dont understand
kvv77 [185]

QUESTION 1

The given inequality is  

y\leq x-3 and y\geq -x-2.

If (3,-2) is a solution; then it must satisfy both inequalities.

We put x=3 and y=-2 in to both inequalities.

-2\leq 3-3 and -2\geq -3-2.

-2\leq 0:True and -2\geq -5:True

Both inequalities are satisfied, hence (3,-2) is a solution to the given system of inequality.

QUESTION 2

The given inequality is  

y\:>\:-3x+3 and y\:>\: x+2.

If (1,4) is a solution; then it must satisfy both inequalities.

We put x=1 and y=4 in to both inequalities.

4\:>\:-3(1)+3 and 4\:>\: 1+2.

4\:>\:0:True and 4\:>\: 3:True

Both inequalities are satisfied, hence (1,4) is a solution to the given system of inequality.

Ans: True

QUESTION 3

The given inequality is  

y\leq 3x-6 and y\:>\: -4x+2.

If (0,-2) is a solution; then it must satisfy both inequalities.

We put x=0 and y=-2 in to both inequalities.

-2\leq 3(0)-6 and -2\:>\: -4(0)+2.

-2\leq -6:False and -2\:>\:2:False

Both inequalities are not satisfied, hence (0,-2) is a solution to the given system of inequality.

Ans:False

QUESTION 4

The given inequality is  

2x-y\: and x+y\:>\:-1.

If (0,3) is a solution; then it must satisfy both inequalities.

We put x=0 and y=3 in to both inequalities.

2(0)-3\: and 0+3\:>\:-1.

-3\::True and 3\:>\:-1: True

Both inequalities are satisfied, hence (0,3) is a solution to the given system of inequality.

Ans:True

QUESTION 5

The given system of inequality is  

y\:>\:2x-3 and y\:.

If (-3,0) is a solution; then it must satisfy both inequalities.

We put x=-3 and y=0 in to both inequalities.

0\:>\:2(-3)-3 and 0\:.

0\:>\:-9;True and 0\::True

Both inequalities are satisfied, hence (-3,0) is a solution to the given system of inequality.

Ans:True

3 0
3 years ago
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