Question

(TCO-8) A band-pass filter has fC1 = 5 kHz and fC2 = 88 kHz. Calculate Bandwidth (BW) and center frequency (fo) for this filter.

Answer 1

Bandwidth is the difference between the upper and lower frequencies in a continuous band of frequencies.

Mathematically can be expressed as,

$BW = F_{c2}-F_{c1}$

The upper frequency is 88Hz and the lower frequency is 6, therefore the Bandwidth would be,

$BW = (88-5)kHz$

$BW = 83kHz$

The center frequency is given on the basis of the square root of the multiplication of the two reference frequencies, then,

$f_0 = \sqrt{f_{c1}*f_{c2}}$

$f_0 = \sqrt{88*5}$

$f_0 = 20.97kHz$