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3 years ago

T or F: In situations of inhalation poisoning, you should call for help before you attempt a rescue.

Physics

1 answer:

siniylev [52]3 years ago

5 0

Answer:

True

Explanation:

When attempting to rescue an individual who is suffering from inhalation poisoning you could possibly do more harm than good. It is advised to call professionals and experts within that field to prevent further damage.

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The moon completes one (circular) orbit of the earth in 27.3 days. The distance from the earth to the moon is 3.84×108 m. What i

I am Lyosha [343]

Answer:

$2.72\cdot 10^{-3} m/s^2$

Explanation:

Let's start by calculating the angular velocity of the Moon. We know that the period is:

$T=27.3 d \cdot 24 \cdot 60 \cdot 60 =2.36\cdot 10^6 s$

So now we can calculate its angular velocity:

$\omega=\frac{2\pi}{T}=\frac{2\pi}{(2.36\cdot 10^6)}=2.66 \cdot 10^{-6} rad/s$

The centripetal acceleration is given by

$a=\omega^2 r$

where

$\omega=2.66\cdot 10^{-6}rad/s$

$r=3.84\cdot 10^8 m$ is the radius of the orbit

Substituting,

$a=(2.66\cdot 10^{-6})^2(3.84\cdot 10^8)=2.72\cdot 10^{-3} m/s^2$

4 0

3 years ago

The relationship among speed, distance, and time is

alexdok [17]

Distance= speed (multiplied by) time

3 0

3 years ago

Read 2 more answers

Two trains move towards each other on a straight track/railroad. The left train has a constant speed of 29ms, the right train ha

laiz [17]

Answer:

The left train travels 2378 m until it reaches the meeting point.

Explanation:

The equation for the position of the trains is the following:

x = x0 + v · t

Where:

x = position at time t

x0 = initial position

v = velocity

t = time

If we place the origin of the frame of reference at the initial position of the left train, the right train will be at an initial position of 4744. 6 m relative to the left train. The velocity of the right train will be negative because it will be heading towards the origin.

At the meeting point, the position of both trains is the same:

x left train = x right train

x0₁ + v₁ ·t = x0₂ + v₂ · t

0m + 29 m/s · t = 4744.6 m - 29 m/s · t

58 m/s · t = 4744.6 m

t = 4744.6 m / 58 /s

t = 82 s

The position of the left train at that time will be:

x = x0 + v · t

x = 0 m + 29 m/s · 82 s

x = 2378 m

The left train travels 2378 m until it reaches the meeting point.

7 0

3 years ago

A ball rolls off a level table with a speed of 2.2 m/s. The table is 1.2 meters high. How far away from the base of the table do

r-ruslan [8.4K]

The base of table is "1.08856 m" far away from the ball land.

Given:

Distance travelled by ball,

S = 1.2 m

Initial velocity,

u = 0 m/s

Acceleration,

a = 9.8 m/s²

Constant speed,

2.2 m/s

As we know the formula,

→ $S = ut+\frac{1}{2}at^2$

By substituting the values, we get

→ $1.2=\frac{1}{2}\times 9.8t^2$

→ $1.2 = 4.9 t^2$

→ $t = \sqrt{\frac{1.2}{4.9} }$

→ $= 0.4948 \ seconds$

Let,

Horizontal distance will be "x".
Time = t

→ $x = 2.2\times t$

$= 2.2\times 0.4948$

$= 1.08856 \ m$

Thus the solution above is right.

Learn more:

brainly.com/question/19170664

8 0

3 years ago

A frog jumps vertically upward from a 20m tall building with an initial velocity of 8.1m/s. How high above the ground will the f

topjm [15]

Answer:

Explanation:

Consider the initial position of the frog (20 m above ground) as the reference position. All measurements are positive measured upward.

Therefore,

u = 10 m/s, initial upward velocity.

H = - 20 m, position of the ground.

g = 9.8 m/s², acceleration due to gravity.

Part (a)

When the frog reaches a maximum height of h from the reference position, its velocity is zero. Therefore

u² - 2gh = 0

h = u²/(2g) = 10²/(2*9.8) = 5.102 m

At maximum height, the frog will be 20 + 5.102 = 25.102 m above ground.

Answer: 25.1 m above ground

Part (b)

Let v = the velocity when the frog hits the ground. Then

v² = u² - 2gH

v² = 10² - 2*9.8*(-20) = 492

v = 22.18 m/s

Answer: The frog hits the ground with a velocity of 22.2 m/s

8 0

4 years ago