How much heat is required to raise 100 grams of water (c= 4.18) by 5 degrees Celsius?
1 answer:
Answer:
Heat capacity, Q = 2090 Joules.
Explanation:
Given the following data;
Mass = 100 grams
Specific heat capacity = 4.18 J/g°C.
Temperature = 5°C
To find the quantity of heat required;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
t represents the temperature of an object.
Substituting into the formula, we have;
Heat capacity, Q = 2090 Joules.
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Answer:
b. Constant magnitude, but varying direction, perpendicular to the equipotential.
Explanation:
As we know that the relation between electric field and electric potential is given as
here if we say that potential is constant because electric field sensor is moving along equi-potential line.
Then we will say
V = constant
so we have
so electric field will remain constant always in magnitude and always remains perpendicular to the surface
so we have
b. Constant magnitude, but varying direction, perpendicular to the equipotential.