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rjkz [21]
3 years ago
10

Oliver Industries is evaluating the manufacturing process for one of their products. Oliver has determined that the process has

yearly maintenance costs of exist29,000, yearly operating costs of exist22,000, and yearly revenues of exist97,000. Two years ago, the firm spent exist6,000 upgrading the equipment used to make this product, and it expects to spend exist5,000 on additional upgrades three years from now. In this scenario, Oliver:_____.
a) has sunk costs of exist5,000.
b) has sunk costs of exist6,000.
c) has sunk costs of exist51,000.
d) does not have any sunk costs.
Business
1 answer:
kifflom [539]3 years ago
6 0

Answer:

b) has sunk costs of exist6,000.

Explanation:

The cost which already been incurred and does not effect the decision being made. This cost is prospective cost. It can be avoided in decision making process.

Sunk Cost

Upgradation of Equipment = $6,000

Other cost are the routine costs which incur every year and future cost which is expected to be incur.

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What is the largest type of financial institution ?
Alecsey [184]
1.) Commercial Bank
2.)Advisory Firms
3.)Mutual Funds
4.)Insurance Companies
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2 years ago
In Agile projects, detailed risk planning occurs during iteration planning, daily-up meetings, and retrospectives. True False
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8 0
3 years ago
Suppose someone borrows $552,000 today to buy a house in Davis, CA. If the annual interest rate is 4%, with monthly compounding,
galina1969 [7]

Answer:

Monthly Repayment on Loan  = $2634.06

Explanation:

given data

principal =  $552,000

annual interest rate = 4% = 0.333% monthly

solution

for get here fair value monthly mortgage payment we consider here time period is 30 year = 360 months

so now we apply here Monthly Repayment on Loan formula that is

Monthly Repayment on Loan  = principal ×  \frac{r(1+r)^t}{(1+r)^t -1}    .................1

put here value and we get

Monthly Repayment on Loan  = 552000 × \frac{r(1+0.333)^{360}}{(1+0.333)^{360} -1}    

Monthly Repayment on Loan  = $2634.06

4 0
3 years ago
7. You have saved $4,000 for a down payment on a new car. The largest monthly payment you can affort is $350. The loan will have
nordsb [41]

Answer:

$13,290.89  and $15,734.26

Explanation:

In this question we have to use the Present value function which is shown on the attachment below:

In the first case

Provided that

Future value = $0

Rate of interest = 12%  ÷ 12 months = 1%

NPER = 48 months

PMT = $350

The formula is shown below:

= PV(Rate;NPER;PMT;FV;type)

So, after solving this, the present value is $13,290.89

In the second case

Provided that

Future value = $0

Rate of interest = 12%  ÷ 12 months = 1%

NPER = 60 months

PMT = $350

The formula is shown below:

= PV(Rate;NPER;PMT;FV;type)

So, after solving this, the present value is $15,734.26

8 0
3 years ago
Zoe Corporation has the following information for the month of March: Purchases $92,000 Materials inventory, March 1 6,000 Mater
Fed [463]

Answer:

Explanation:

The preparation of the cost of goods manufactured is presented below:

Zoe Corporation

Statement of Cost of Goods Manufactured

For Month Ended March 31, 20XX

Work in process inventory March 1   $22,000

Direct materials :    

Materials inventory, March 1  $6,000  

Add: Purchases       $92,000  

Cost of materials for use $98,000  

Less - materials inventory, March 31 -$8,000  

cost of materials placed in production $90,000  

Add:

Direct labor  $25,000  

Factory overhead  $37.000  

Total manufacturing costs added  $152,000

Total manufacturing costs     $174,000

Less- work in process inventory, March 31  $23,500

Cost of goods manufactured   $150,500

7 0
3 years ago
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