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zvonat [6]
3 years ago
14

How do I complete this factor? 16x^2-18=

Mathematics
2 answers:
Luda [366]3 years ago
7 0

To factor 16x^2-18, recognize that this could be regarded as the difference of two squares: 16x^2-18 = (4x)^2 - (√18)^2.

Follow this pattern for the difference of two squares: a^2 - b^2 = (a - b)(a + b)

Thus, (4x)^2 - (√18)^2 = (4x + √18)(4x - √18)

Note that √18 can be reduced to 3√2.

Therefore, the factors in simplest form are (4x + 3√2) and (4x - 3√2).

aalyn [17]3 years ago
5 0

To factor 16x^2-18, recognize that this could be regarded as the difference of two squares: 16x^2-18 = (4x)^2 - (√18)^2.

Follow this pattern for the difference of two squares: a^2 - b^2 = (a - b)(a + b)

Thus, (4x)^2 - (√18)^2 = (4x + √18)(4x - √18)

Note that √18 can be reduced to 3√2.

Read more on Brainly.com - brainly.com/question/10700475#readmoreTo factor 16x^2-18, recognize that this could be regarded as the difference of two squares: 16x^2-18 = (4x)^2 - (√18)^2.

Follow this pattern for the difference of two squares: a^2 - b^2 = (a - b)(a + b)

Thus, (4x)^2 - (√18)^2 = (4x + √18)(4x - √18)

Note that √18 can be reduced to 3√2.

Read more on Brainly.com - brainly.com/question/10700475#readmore

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