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insens350 [35]
3 years ago
14

Milk and cream are mixed together for a recipe. The total volume of the mixture is 1 cup. If the milk contains 2% fat, the cream

contains 18% fat, and the mixture contains 6% fat, how much cream is in the mixture?
Mathematics
1 answer:
irina1246 [14]3 years ago
4 0

So this is a solution problem the answer is 3/4 cups or 75% milk and 1/4 cups or 25% cream, here's why:

m = milk

c = cream


m + c = 1

This is because when you add milk and cream then you get one cup of solution


.02m + .18c = .06

When you add together the percentages the goal is to have .06 or 6%


100m + 100c = 100

2m + 18c = 6

I do this to make it easier to solve

200m + 200c = 200

-200m - 1800c = -600

The "m's" cancel out

-1600c = -400

c = 1/4 or .25 or 25%


Now we add c back in

m + 1/4 = 1

Solve for m

m = 3/4


Thus: 3/4 milk and 1/4 cream

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luda_lava [24]

Answer:

mean = 15. 14 or 15

median= 14

range = 25

5 0
3 years ago
Need help with this math
olganol [36]

Hi,

Here is the solution.

3 years = 36 months

Leased amount for 3 years = $3000 + 36*350

= $3000 + $12600

Leased amount for 3 years = $15600

Residual value = $12000

Assume you didn't buy the car, you took it for lease, so your expense = $15600.

Now Assume you bought the car for $21,000.

After using 3 years, you can sell it for $12000.

Your expense = $21,000 - $12,000 = $9000.

Conclusion:

It is less expensive to buy the car.

The cost for buying the car and selling it after 3 years = $9000.

Hope you will understand the steps. Thank you :)

3 0
3 years ago
John made 3 more free throws than Jose. The
jeyben [28]
25-3=22

22/2 = 11

John made 14 free throws while Jose made 11.
5 0
4 years ago
Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball
Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and 51\frac{1}{3} yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from 51\frac{1}{3} yards.

\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}

Let us have a common denominator.

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}  

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}

\text{1 yard}=3\text{ feet}

\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}

\frac{28}{3}\text{ yards}=28\text{ feet}

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0
4 years ago
8x+4 (4x+3) = 4 (6x+4)-4 help
Tasya [4]

Answer:

0

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

8x+4(4x+3)=4(6x+4)−4

8x+(4)(4x)+(4)(3)=(4)(6x)+(4)(4)+−4(Distribute)

8x+16x+12=24x+16+−4

(8x+16x)+(12)=(24x)+(16+−4)(Combine Like Terms)

24x+12=24x+12

24x+12=24x+12

Step 2: Subtract 24x from both sides.

24x+12−24x=24x+12−24x

12=12

Step 3: Subtract 12 from both sides.

12−12=12−12

0=0

Answer:

All real numbers are solutions.

4 0
3 years ago
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