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madam [21]
3 years ago
13

8x+4 (4x+3) = 4 (6x+4)-4 help

Mathematics
1 answer:
Tasya [4]3 years ago
4 0

Answer:

0

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

8x+4(4x+3)=4(6x+4)−4

8x+(4)(4x)+(4)(3)=(4)(6x)+(4)(4)+−4(Distribute)

8x+16x+12=24x+16+−4

(8x+16x)+(12)=(24x)+(16+−4)(Combine Like Terms)

24x+12=24x+12

24x+12=24x+12

Step 2: Subtract 24x from both sides.

24x+12−24x=24x+12−24x

12=12

Step 3: Subtract 12 from both sides.

12−12=12−12

0=0

Answer:

All real numbers are solutions.

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tatiyna

9514 1404 393

Answer:

  x = 33

Step-by-step explanation:

The angles are complementary.

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Suppose you know that the volume of the following prism is represent by V(x) = -2x^3 + 14x^2 + 120x.
erastova [34]

Step-by-step explanation:

-2x³ + 14x² + 120x

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When using a graphing calculator to maximise the volume of the prism, we get x = 7.378. However this value is not reasonable as it makes -2x and (x - 12) negative, which are the sides of the prism.

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3 years ago
State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle
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Answer:

The interval notation for the domain is [\frac{23}{3},\infty  ].

Step-by-step explanation:

Consider the provided information.

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We need to find the value of f\left(g\left(x\right)\right).

Put the value of g(x) in  f\left(g\left(x\right)\right).

f\left(g\left(x\right)\right)=f(x-7)  ....(1)

Now, put x=x-7 in \:f\left(x\right)=\sqrt{3x-2}

\:f\left(x-7\right)= \sqrt{3(x-7)-2}

\:f\left(x-7\right)= \sqrt{3x-21-2}

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From equation 1.

f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}

The domain of the function is the set of input values for which a function is defined.

Here, the value of 3x-23 should be greater or equal to 0 as the square root of a negative number is not real.

Domain= 3x-23\geq0

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The value of x is all real number greater than \frac{23}{3}.

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Dafna11 [192]

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Step-by-step explanation:

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Answer:

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