3/8 of the rows are empty. The three rows that are empty (3) would be in the numerator while the total amount of rows (8) would be in the denominator.

8 0

3 years ago

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I want to know the work of this, like the process. Please

pogonyaev

In this question, you know that the machine packs $\frac{2}{3}$ of a box every $\frac{1}{2}$ of a minute. Since it is constant, you simply have to double the half a minute to a full minute and then also double the rate to get $\frac{4}{3}$ boxes packed per minute. And $\frac{4}{3}$ is equal to $1\frac{1}{3}$

3 0

3 years ago

An architect wants to draw a rectangle with a diagonal of 13 centimeters. The length of the rectangle is to be 3 centimeters mor

butalik [34]

Answer:

The rectangle is 3.2 cm by 12.6 cm

Step-by-step explanation:

See attached image for a diagram.

Choose w to represent the width because the length is described by referring to the width: it's 3 more than (add 3) triple (multiplied by 3) the width.

Length = 3w + 3

The diagonal forms two right triangles, each with leg = w, other leg = 3w + 3, hypotenuse = 13.

The Pythagorean Theorem says $(\text{leg})^2+(\text{leg})^2=(\text{hypotenuse})^2$ so

$w^2+(3w+3)^2=13^2\\\\w^2+9w^2+18w+9=169\\\\10w^2+18w-160=0\\\\5w^2+9w-80=0\\$

Now solve using the Quadratic Formula with $a=5,\,b=9,\,c=-80$ .

$w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\w=\frac{-9\pm\sqrt{81+1600}}{10}\\\\w=\frac{-9\pm\sqrt{1681}}{10}\\\\w=\frac{-9\pm41}{10}\\\\w=-5\text{ or }w=3.2$

The negative root makes no sense as a distance, so the width of the rectangle is 3.2 cm. The length is 3(3.2) + 3 = 12.6 cm.

5 0

3 years ago

Please help I'm really confused I need have with these 6 questions

Lelechka [254]

Ahh, basic shapes. Split up the weird shapes into easier ones. #1 can be truned into 2 trapezoids. #2 can be turned into 2 circles. #3 is a triangle and a trapezoid. #4 is 2 right triangles. #5 is a rectangel and a traingle. Finally, #6 is 3 traigles and a rectangle. Do you see how we broke the hard shapes into easier shapes?

6 0

3 years ago