All categories

2 years ago

A line goes through the points (5, -1) and (7, -5). What is a possible equation to a new line that is perpendicular?

Mathematics

1 answer:

GuDViN [60]2 years ago

6 0

Step-by-step explanation:Equation of line perpendicular to , x=4 is

y +k=0

As, keep in mind , the equation of line perpendicular to , ax + by +c=0 is b x - a y +c=0

As, given the line perpendicular to, x =4, passes through the point (5,7).

So, y+k =0, passes through (5,7).

→ 7 +k=0

→ k= -7

So, line perpendicular to x=4, which passes through the point (5,7) is →y-7=0 that is y=7.

You might be interested in

Solve x^2 + 5x + 6 = 0 mathswatch

zhuklara [117]

Answer:

x= -2

x= -3

Step-by-step explanation:

4 0

2 years ago

What is the product?

RSB [31]

Answer:

15a^5b^15

Step-by-step explanation:

you multiply 5 and 3 to get 15, and then when you are multiplying exponents of variables, you actually add them, so a^2 times a^3 is actually a^5, and b^7 times b^8 is b^15. Because these are all multiplied together, you get the answer of 15a^5b^15.

4 0

2 years ago

Read 2 more answers

Complete the equation: x2 + 8x + __ = (__)^2

Setler79 [48]

Answer:

Step-by-step explanation:

16,x+4

by completing square formula

6 0

2 years ago

Find the discriminant and the numbers of real roots for this equation: 4x^2+12x+9=0

Len [333]

Answer:

$D=0$

The quadratic equation has one real root with a multiplicity of 2.

Step-by-step explanation:

Given a quadratic equation:

$ax^2+bx+c=0$

You can find the Discriminant with this formula:

$D=b^2-4ac$

<em> </em>In this case you have the following quadratic equation:

$4x^2+12x+9=0$

Where:

$a=4\\b=12\\c=9$

Therefore, when you substitute these values into the formula, you get that the discriminant is this:

$D=(12)^2-4(4)(9)\\\\D=0$

Since $D=0$ , the quadratic equation has one real root with a multiplicity of 2 .

8 0

2 years ago

TRIGNONMETRY

pishuonlain [190]

Answer:

i like ur pp

Step-by-step explanation:

6 0

2 years ago