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alexandr402 [8]
2 years ago
10

A line goes through the points (5, -1) and (7, -5). What is a possible equation to a new line that is perpendicular?

Mathematics
1 answer:
GuDViN [60]2 years ago
6 0

Step-by-step explanation:Equation of line perpendicular to , x=4 is

y +k=0

As, keep in mind , the equation of line perpendicular to , ax + by +c=0 is b x - a y +c=0

As, given the line perpendicular to, x =4, passes through the point (5,7).

So, y+k =0, passes through (5,7).

→ 7 +k=0

→ k= -7

So, line perpendicular to x=4, which passes through the point (5,7) is →y-7=0 that is y=7.

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This is a very interesting question.  Draw a line from the origin to where the upper right vertex of the square touches the line. That line has the property that the its equation is y = x. So the "solution" to the point of intersection is the solution of the two equations.

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<em><u>x intercept</u></em>

The x intercept occurs when y = 0

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