X^3(1/y^2)-4 is (x^3y^-2)-4 simplified with only positive exponents
Answer:
7th
Step-by-step explanation:
63 - 58 = 5
68-63 = 5
She is adding 5 points each time
a1 = 58
d = 5
a2 = 63
a3 = 68
a4 = 58+5 = 73
a5 = 73+5 = 78
a6 = 78+5 = 83
a7 = 83+5 = 88
This is the first assessment greater then 85, so the 7th assessment
Answer:
Step-by-step explanation:
We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population
That means total number of students being surveyed is 13+13=26 students
Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13
The probability distribution is shown in the table below. Let be the number of pets and is the probability of owning the number of pets
