In a genetic experiment on peas, one sample of offspring contained 436 green peas and 171 yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3/4 that was expected? The probability of getting a green pea is approximately: Is the probability reasonably close to 3/4?

Answer:

The probability is $P(g) =0.72$

Yes the result is reasonably close

Step-by-step explanation:

From the question we are told that

The number of of green peas is $g = 436$

The number of yellow peas is $y = 171$

The sample size is $n = 171 + 436 = 607$

The probability of getting an offspring pea that is green is mathematically represented as

$P(g) = \frac{g}{n}$

$P(g) = \frac{436}{607}$

$P(g) =0.72$

Comparing $P(g) =0.72$ to $\frac{3}{4} = 0.75$ we see that the result is reasonably close

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Which of the following provides the best description of the function of genes?

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Answer: A

Step-by-step explanation:

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Find the first two expressions in the sequence ___, ___, 4x+5, 5x+7, 6x+9, 7x+11, 8x+13...

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You can see that you add 1x to each expression in the sequence, which means that the first expression will be 2x, and the second one 3x. You also add 2 to each x, which means that the first expression will be 1, and the second one 2.
2x+1, 3x+3, 4x+5, 5x+7, 6x+9, 7x+11, 8x+13....

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