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stiks02 [169]
3 years ago
14

These are the values in Min-Su’s data set.

Mathematics
1 answer:
Ber [7]3 years ago
3 0
The answer is (4,5) (5,-5) (6,-4) (7,3) (8,1).
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The square root 30 lie between what two numbers
Debora [2.8K]
The square root of thirty lies between the numbers 5 and 6.
8 0
3 years ago
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
Can somebody help me with this?<br>​
miv72 [106K]

Answer:

Its y=1/2x +2(the second one)

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Someone please help me with two answer choices
otez555 [7]

Answer:

It is the first and the last three.

7 0
3 years ago
1.2and 1.4 which one bigger
Hitman42 [59]
Isn't it 1.4 because I'm thinking its 1,400 and 1.2 is 1,200
4 0
3 years ago
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