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3 years ago

The polynomial (x - 2) is a factor of the polynomial 4x2 - 6x-4. True or false?

Mathematics

1 answer:

Colt1911 [192]3 years ago

3 0

True, x-2 is a factor

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1/5x + 4 =1/3x-8 <br> Can you show your work too? That would be great

Vikentia [17]

Answer:

Step-by-step explanation:

1/5x+4=1/3x-8

add 8 to both sides and subtract 1/5x from both sides

4+8=1/3x-1/5x

12=5/15x-3/15x

12=2/15x

divide both sides by 2/15

12÷2/15=x

when dividing by a fraction, invert and multiply

12*15/2=x

90=x

CHECK:

1/5(90)+4=1/3(90)-8

18+4=30-8

22=22

5 0

3 years ago

How to numerically write five and eight then multiply by 4

lozanna [386]

Answer:

5 + 8 × 4

Assuming "five and eight" means 5 + 8

8 0

3 years ago

A baker has 6 small bags of flour. Each bag weighs 1 pound. She divides each bag into thirds. How many 1/3 - pound bags of flour

lana [24]

Answer:

18 smaller bags

Step-by-step explanation:

Each one pound bag becomes 3 one-third pound bags.

So 6 one pound bags will become 6×3=18 one-third pound bags.

5 0

4 years ago

To convert 70 minutes to seconds, you would use the ratio a. true b. false

Angelina_Jolie [31]

True, you would use the ratio of minutes to seconds.

8 0

3 years ago

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

$\rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]$

5 0

3 years ago