Answer:
n=7
Step-by-step explanation:
I feel like you need the answer now so i'm not gonna write one.
Step-by-step explanation:
5x90=450
700-450=250
250/5=50
50 more tickets.
i don't know if that's in an inequality form or not. but that's how many tickets
Answer:
37%
Step-by-step explanation:
If Ramona received an overall pay of $52,561 last year, $23,960 of which was base pay, we can first subtract these two numbers to find the amount she made from her sales commission:
$52,561 - $23,960 = $28,601
In order to find her percent commission, we can set up a proportion:
, where 'p' is her rate of commission
Cross-multiply and divide: 100(28601) = 77300x or 2,860,100 = 77,300x
Or x = 37%
2hr=$12
1hr=12/2= $6/hr
$36=1hr/$6= 6hr for $36
If he worked 3hr he would get (6*3)= $18
If he worked 4 hours he would get (6*4)= $24
I hope this answers your question
Answer:
0.35% of students from this school earn scores that satisfy the admission requirement.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard deviation of 302.
This means that 
The local college includes a minimum score of 2294 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement?
The proportion is 1 subtracted by the pvalue of Z when X = 2294. So



has a pvalue of 0.9965
1 - 0.9965 = 0.0035
0.0035*100% = 0.35%
0.35% of students from this school earn scores that satisfy the admission requirement.