Question

The points (3,0) and (6,4) are adjacent vertices of a square, What is the area of the square, in unit squared? HELP PLS

Answer 1

Answer: 25

Step-by-step explanation:

Find the distance from (3, 0) to (6,4).  That is the side length (s).

Area (A) = s²

$s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\s^2=(x_2-x_1)^2+(y_2-y_1)^2\\\\s^2=(6-3)^2+(4-0)^2\\\\s^2=3^2+4^2\\\\s^2=9+16\\\\s^2=25\\\\\\A=s^2\\\\\large\boxed{A = 25}$

Answer 2

Answer:

25 units squared

Step-by-step explanation:

Distance between (3, 0) and (6, 4)

√(3-6)²+(0-4)² = 5

Area = 5 * 5 = 25 units squared