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SOVA2 [1]
3 years ago
12

Write three different improper fractions that equal 4 1/2

Mathematics
2 answers:
salantis [7]3 years ago
6 0
18/4ths, 27/6ths, and 36/8ths.
cupoosta [38]3 years ago
5 0
4 1/2
4 1/2=9/2
4 1/2=18/4
4 1/2=36/8
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3 years ago
What’s the area of a square the side is 7x-3
Gnoma [55]

Area of a square = Side × Side

Side = 7x-3

Area of the square = (7x-3) × (7x-3)

= 7x(7x-3) -3(7x-3)

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3 years ago
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WARRIOR [948]

Answer:

2\,(x-1)^2=4

which is the first option in the list of possible answers.

Step-by-step explanation:

Recall that the minimum of a parabola generated by a quadratic expression is at the vertex of the parabola, and the formula for the vertex of a quadratic of the general form:

y=ax^2+bx+c

is at   x_{vertex}=\frac{-b}{2\,a}

For our case, where a=2\,\,, b=-4\,\,,\,\,and \,\,c=-2  we have:

x_{vertex}=\frac{-b}{2\,a}\\x_{vertex}=\frac{4}{2\,*\,2}\\x_{vertex}=1

And when x = 1, the value of "y" is:

y(x)=2x^2-4x-2\\y(1)=2(1)^2-4(1)-2\\y(1)=2-6\\y(1)=-4\\y_{vertex}=-4

Recall now that we can write the quadratic in what is called: "vertex form" using the coordinates (x_{vertex},y_{vertex)of the vertex as follows:

y-y_{vertex}=a\,(x-x_{vertex})^2

Then, for our case:

y-(-4)=2\,(x-1)^2\\y=2\,(x-1)^2-4

Then, for the quadratic equal to zero as requested in the problem, we have:

y=2\,(x-1)^2-4=0\\2\,(x-1)^2-4=0\\2\,(x-1)^2=4

5 0
3 years ago
Point K is graphed on a number line at 3. Point L is 11 units away from point K on the number line.
notsponge [240]
3+/-11
add 11 to 3
11+3=14
minus 11 from 3
3-11=-8

the coordinate could be 14 or -8
6 0
3 years ago
Write 350 as a product of primes. Use index notation when giving your answer
Mkey [24]

Answer:

5² x 7 x 2

Step-by-step explanation:

350

= 35 x 10

= 7 x 5 x 5 x 2

= 5² x 7 x 2

8 0
3 years ago
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