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Diano4ka-milaya [45]
3 years ago
14

Simplify 4c - 5c + 6c

Mathematics
1 answer:
elixir [45]3 years ago
3 0
Really !  Why do you let math scare you like that ? ?

How about this:       (4 cows) - (5 cows) + (6 cows)

I'll bet you have no problem seeing that it's  5 cows .

So why do you totally clutch when they're just  C's  instead of cows ? ?
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Multiply 3x (2x - 1)​
Volgvan

Answer:

6x^2 - 3x

6x^2-3x

Step-by-step explanation:

3x (2x-1)

multiply 3x by 2x -> 6x^2

multiply 3x by -1 -> -3x

6 0
2 years ago
Read 2 more answers
5(-1x+5)=10 pls help
Leya [2.2K]

Answer:

-5x+5=10

-5x=10-5

-5x=5

x=-5/5

x=-1

7 0
3 years ago
Read 2 more answers
Select the correct answer.
Nat2105 [25]

Answer:

Step-by-step explanation:

Both distances are in the scientific notation:

Earth - Sun = 9.3 * 10^7 miles

Saturn - Sun = 8.87 * 10^8 miles

8.87 * 10^8 - 9.3 * 10^7 =

= 88.7 *10^7 - 9.3 * 10^7 =

= 79.4 * 10^7 = 7.94 * 10 ^8 = 794,000,000 miles

Answer: Saturn is  7.94 * 10^8 miles farther from Sun than Earth is.

6 0
2 years ago
Rhett decides to build a square room for his movie and music collection. If the area of the room is 9x2 − 6x + 1 square feet, wh
Marina86 [1]

If the area of the room is 9x2 − 6x + 1 square feet, then the length of one<span> side of the room is <span>(3x − 1) feet. </span></span>The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

3 0
3 years ago
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In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
2 years ago
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