![\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) \\\\ a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} 729=27^2\\ \qquad (3^3)^2\\ 1000=10^3 \end{cases}\implies 729^{15}+1000\implies ((3^3)^2)^{15}+10^3 \\\\\\ ((3^2)^{15})^3+10^3\implies (3^{30})^3+10^3\implies (3^{30}+10)~~[(3^{30})^2-(3^{30})(10)+10^2] \\\\\\ (3^{30})^3+10^3\implies (3^{30}+10)~~~~[(3^{60})-(3^{30})(10)+10^2]](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bdifference%20and%20sum%20of%20cubes%7D%20%5C%5C%5C%5C%20a%5E3%2Bb%5E3%20%3D%20%28a%2Bb%29%28a%5E2-ab%2Bb%5E2%29%20%5C%5C%5C%5C%20a%5E3-b%5E3%20%3D%20%28a-b%29%28a%5E2%2Bab%2Bb%5E2%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20729%3D27%5E2%5C%5C%20%5Cqquad%20%283%5E3%29%5E2%5C%5C%201000%3D10%5E3%20%5Cend%7Bcases%7D%5Cimplies%20729%5E%7B15%7D%2B1000%5Cimplies%20%28%283%5E3%29%5E2%29%5E%7B15%7D%2B10%5E3%20%5C%5C%5C%5C%5C%5C%20%28%283%5E2%29%5E%7B15%7D%29%5E3%2B10%5E3%5Cimplies%20%283%5E%7B30%7D%29%5E3%2B10%5E3%5Cimplies%20%283%5E%7B30%7D%2B10%29~~%5B%283%5E%7B30%7D%29%5E2-%283%5E%7B30%7D%29%2810%29%2B10%5E2%5D%20%5C%5C%5C%5C%5C%5C%20%283%5E%7B30%7D%29%5E3%2B10%5E3%5Cimplies%20%283%5E%7B30%7D%2B10%29~~~~%5B%283%5E%7B60%7D%29-%283%5E%7B30%7D%29%2810%29%2B10%5E2%5D)
now, we could expand them, but there's no need, since it's just factoring.
Answer:
11x^2-8x-14
Step-by-step explanation:
(2x^2- 8x– 6)+(9x^2-8) = 11x^2-8x-14
Answer:
<h2>A) Height is the missing measurment.</h2><h2 /><h2> B) 1,400= 20 × 14 × H</h2><h2 /><h2>C) 1400 ÷ H = 280</h2>
Step-by-step explanation:
A) Length × Width × Height
B) V is 1,400
L is 20
W is 14
H is unknown so use a variable
C) 20 × 14= 280.
Option B is correct. <em>Yes,</em><em> (9, 22) is a solution to the </em><em>inequalities</em><em> and the</em><em> measurements</em><em> will fit in the space. </em>
The formula for calculating the perimeter of the rectangular fence is expressed as:
A = 2(L + W) where:
L is the length
W is the width
If Jamie can afford at most 70feet to build a rectangular fence is expressed as:
2L + 2W ≤ 70
<em>We are to check if the garden measure 9 feet by 22 feet. To do this we are to substitute L = 9 and W = 22 into the formula to check if the result will be less than 70</em>
On substituting:
= 2(9) + 2(22)
= 18 + 44
= 62 feet
Since 63 feet is less than 70 feet, hence we can conclude that <em>Yes,</em><em> (9, 22) is a solution to the </em><em>inequalities</em><em> and the</em><em> measurements</em><em> will fit in the space. </em>
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<em>Learn more here: brainly.com/question/17229451</em>
Mean is the "meanest" because it requires the most work. Add up the values in your data set and divide by the number of terms in the data.
Let x represent attendees at Harry's Hoedown, then
Mean = 
41 = 
123 = 48 + 33 + x
123 = 81 + x
42 = x
Answer: 42