Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
Answer:
A. 9 sqrt 2
Explanation:
Plug in hypotenuse and given side into
a^2 + b^2 = c^2 and solve.
Hey there the answer is,
<span>The Greates Common Factor (GCF) is: 7
</span>
Hope I helped!!!<3
Answer:
no identity will escape! I know where you live
