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3 years ago

A linear cost function is c(x) = 4x + 300.what is the cost of producing one more item if 50 are currently being produced?

Mathematics

1 answer:

lakkis [162]3 years ago

7 0

Sent a picture of the solution to the problem (s).

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The expression (4c − 3d)(3c + d) is equivalent to:

Umnica [9.8K]

(4c - 3d)(3c + d) =

= 12c² + 4cd - 9cd - 3d² =

= <u>12c² - 5cd - 3d²</u>

4 0

3 years ago

Help me with this math equation.<br><br>

Stells [14]

8/2•m or to simplify 4m

7 0

3 years ago

Will mark brainliest to whoever answers correctly first!!!

IgorLugansk [536]

To find the volume, you do area multiplied by thickness( or height)
In this example, you do (1/2*9*6)*10 which is 270
hope I helped ;)

7 0

3 years ago

find the ninth term of the geometric sequence, given the first term and the common ratio: a1=1, r=-1/3

olasank [31]

Answer:

0.0001524

Please Mark Brainliest If This Helped!

3 0

3 years ago

Raquel has created a program for a robot. The robot travels 10 meters and stops. The program is designed for wheels that are 2.5

Grace [21]

Answer:

Raquel should adjust the number of rotations to 115.81 rotations

Step-by-step explanation:

step 1

Find the circumference of the wheels that are 2.5 cm in diameter

The circumference is equal to

$C=2\pi r$

we have

$r=2.5/2=1.25\ cm$

assume

$\pi =3.14$

substitute

$C=2(3.14) (1.25)$

$C=7.85\ cm$

step 2

Find the number of rotations

Divide 10 meters by the circumference

$10\ m=1,000\ cm$

$1,000/7.85=127.39\ rotations$

step 3

For a diameter of 2.75 cm find how should she adjust the number of rotations so that the robot travels the same distance

Find the circumference of the wheels

The circumference is equal to

$C=2\pi r$

we have

$r=2.75/2=1.375\ cm$

assume

$\pi =3.14$

substitute

$C=2(3.14) (1.375)$

$C=8.635\ cm$

step 4

Find the number of rotations

Divide 10 meters by the circumference

$10\ m=1,000\ cm$

$1,000/8.635=115.81\ rotations$

3 0

3 years ago