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3 years ago

If f(x)=x+4 and g(x)=2x-3, find (g-f)(2)

Mathematics

2 answers:

nalin [4]3 years ago

6 0

F(x) = x + 4
g(x) = 2x - 3
(g - f)(2) = (2x - 3) - (x + 4)
(g - f)(2) = (2x - x) + (-3 - 4)
(g - f)(2) = x - 7

iragen [17]3 years ago

6 0

F(x)= x+4
g(x)= 2x-3

(g-x)(x) = [2x-3] -[x+4]
= 2x-x-3-4
= x-7

(g-x)(2)= (2)-7
= -5

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3 years ago

Answer the Blanks:

vfiekz [6]

Answer:

1. 90°

2. 90°

3. 40°

4. 45°

5. 45°

Step-by-step explanation:

Given: ΔABC,

CD⊥AB,

m∠A=50°,

m∠ACB=85°

Solution:

1. ∠ADC is a right ange, because CD⊥AB, so

$m\angle ADC=90^{\circ}$

2. ∠CDB is a right ange, because CD⊥AB, so

$m\angle CDB=90^{\circ}$

3. Consider triangle ACD. The sum of the measures of all interior angles is always 180°, so

$m\angle A+m\angle ADC+m\angle ACD=180^{\circ}\\ \\50^{\circ}+90^{\circ}+m\angle ACD=180^{\circ}\\ \\m\angle ACD=180^{\circ}-50^{\circ}-90^{\circ}=40^{\circ}$

4. By Angle Addition Postulate,

$m\angle ACD+m\angle BCD=m\angle ACB\\ \\40^{\circ}+m\angle BCD=85^{\circ}\\ \\m\angle BCD=85^{\circ}-40^{\circ}=45^{\circ}$

5. Consider triangle ABC. The sum of the measures of all interior angles is always 180°, so

$m\angle A+m\angle ACB+m\angle B=180^{\circ}\\ \\50^{\circ}+85^{\circ}+m\angle B=180^{\circ}\\ \\m\angle B=180^{\circ}-50^{\circ}-85^{\circ}=45^{\circ}$