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ch4aika [34]
3 years ago
11

What two angles equal to a complementary angle?

Mathematics
1 answer:
butalik [34]3 years ago
5 0

Answer:

go google and search

Step-by-step explanation:

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A and B are supplementary. A is 20 less than three times the measure of B. What are the measures of A and B?
Amanda [17]

Answer:

∠ A = 130° , ∠ B = 50°

Step-by-step explanation:

supplementary angles sum to 180°

express ∠ A in terms of ∠ B , that is ∠ A = 3∠B - 20 , then

∠ A + ∠ B = 180° , that is

3∠B - 20+ ∠B = 180 ( add 20 to both sides )

4∠B = 200 (divide both sides by 4 )

∠ B = 50°

∠ A = 3 × 50° - 20 = 150° - 20° = 130°

8 0
2 years ago
The probability of winning a new car is 1/500,000. What are the odds against winning the car?
BaLLatris [955]
The odds against winning the car is 500,000/1
4 0
3 years ago
Find an equation of the line that has the given slope and passes through the given point.
Mandarinka [93]
Y = 2x+6
The slope is 2 and the y intercept is 6
6 0
3 years ago
The graph shows the functions f(x), p(x), and g(x):
Zinaida [17]
A) The solutions to this set of equation is where the graphs cross. They cross at point (-3, -2).

B) The solutions for f(x) would be points that fall on the graph of f(x). Two possible points are (-3, -2) and (-7, 3)

C) These 2 functions cross at (4, 1). That is the solution.
3 0
2 years ago
Find the critical numbers of the function f(x) = x6(x − 1)5 what does the first derivative test tell you that the second derivat
patriot [66]
The given function is f(x) = x⁶(x-1)⁵

The first derivative is
f'(x) = 6x⁵(x-1)⁵ + 5x⁶(x-1)⁴
       = x⁵(x-1)⁴(6x - 6 + 5x)
       = x⁵(x-1)⁴(11x - 6)
The critical values are the zeros of f'(x). They are
x = 0, 6/11, and 1.
The critical values indicate that turning points exist for f(x) at the critical points. However, we do not know the nature of the turning points.

Write the first derivative in the form f'(x) = (x-1)⁴(11x⁶ - 6x⁵).
The second derivative is
f''(x) = 4(x-1)³(11x⁶ - 6x⁵) + (x-1)⁴(66x⁵ - 30x⁴)
        = (x-1)³(44x⁶ - 24x⁵ + 66x⁶ - 30x⁵ - 66x⁵ + 30x⁴)
        = (x-1)³(110x⁶ - 120x⁵ + 30x⁴)
        = 10x⁴(x-1)³(11x² - 12x + 3)
The sign of f''(x) at the critical values tell us the nature of the turning point.

f''(0) = 0, therefore a point of inflection exists at x = 0.
f''(6/11) > 0, therefore a local minumum exists at x = 6/11.
f''(1) = 0, therefore a point of inflection exists at x=1.

The graphs shown below confirm these results.

8 0
3 years ago
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