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OlgaM077 [116]
3 years ago
11

What is the length of the side opposite Angle B? 3 units 4 units 5 units 6 units

Mathematics
2 answers:
Juliette [100K]3 years ago
7 0

Answer:

4 units

Step-by-step explanation:

Butoxors [25]3 years ago
5 0

Answer:

4 units

Step-by-step explanation:

I just took the test

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Please help need it asap!!!!!
Vlada [557]

Answer:

A. 6.89 m

Step-by-step explanation:

Pythagorean Theorem.

a^2+b^2=c^2

(1.5)^2 + (3.6)^2 = c^2

2.25 + 12.96 = 15.21

√15.21= 3.9

find the ratio from the the left triangle to the other -

2.65÷1.5= 1.766666 × 3.69 = 6.89

4 0
2 years ago
17. For the parallelogram, find the value of the variables. Show your work. 5x + 2 3y - 6 21 17 24=3y-6 => 30=3y, y=10, 12 =
Dafna11 [192]
In this problem, you have already shown the solution.

24 = 3y - 6 => 30 = 3y, y =10

12 = 5x + 2 => 10 = 5x , x = 2

And yes, basically parallel sides must have the same length

These are the answers:

for 17.) x = 2
y = 10

for 18.) mid segment = (side 1 + side 2) / 2 -->
19 = (24 + side2) / 2 -->
38 = 24 + side2,

thus, side 2 = 14 units
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=if%20x%20%3D%20-5%5C%5Cx%5E%7B2%7D%20%2B%203%5C%5Cx%20-%202" id="TexFormula1" title="if x = -5
levacccp [35]

Answer:

this question is inappropriate

8 0
3 years ago
What is the inverse of the function g(x)=x^3/8+16
shtirl [24]

Answer:

The inverse of the function is f^{-1}(x) = \sqrt[3]{\frac{x-16}{8}}

Step-by-step explanation:

Inverse of a function:

Suppose we have a function y = g(x). To find the inverse, we exchange the values of x and y, and then isolate y.

In this question:

y = \frac{x^3}{8} + 16

Exchanging x and y:

x = \frac{y^3}{8} + 16

\frac{y^3}{8} = x - 16

y^3 = \frac{x-16}{8}

y = \sqrt[3]{\frac{x-16}{8}}

The inverse of the function is f^{-1}(x) = \sqrt[3]{\frac{x-16}{8}}

7 0
3 years ago
PLZ HELP ASAP!!! Will give brainliest if answered correctly with explanation!!!
slavikrds [6]

Answer:  Given.

Step-by-step explanation:  The last sentence of the directions, Begin. . .

ends with:  Construct line RS a bisector of ∠PQR

6 0
3 years ago
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