A package contains 4 red, 2 green, 8 purple, and 6 blue jelly beans. What is the probability of choosing a purple jelly bean,

Mathematics

2 answers:

Irina-Kira [14]3 years ago

6 0

Answer:

I think that the answer is c

Step-by-step explanation:

maxonik [38]3 years ago

4 0

U add them but and the put the color bean
8/20 probably of choosing purple bean
6/20 probably of choosing a blue bean
hope it helps

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DIA [1.3K]

Answer:

$y = \frac{3}{2} x + 13$

Step-by-step explanation:

1) Use point-slope formula $y-y_1 = m (x-x_1)$ to find the slope-intercept form (or y = mx + b form) of the equation. m represents the slope, and $x_1$ and $y_1$ represent the x and y values of a point the line intersects. So, substitute $\frac{3}{2}$ for m, -4 for $x_1$ , and 7 for $y_1$ . Then, simplify and isolate y on the left side like so:

$y-(7) = \frac{3}{2} (x - (-4)) \\y -7 = \frac{3}{2} (x + 4) \\y - 7 = \frac{3}{2} x + 6\\y = \frac{3}{2} x + 13$

3 0

3 years ago

Simplify sin^2y/sec^2 y−1 to a single trigonometric function

liubo4ka [24]

Answer:

$\frac{ { \sin}^{2} y}{ { \sec}^{2}y - 1 } = { \cos }^{2} y$

Step-by-step explanation:

We know that ${ \tan }^{2} y = { \sec }^{2} y - 1$

Also , ${ \tan}^{2} y = \frac{ { \sin }^{2} y}{ { \cos }^{2}y }$

So ,

$\frac{ { \sin }^{2}y }{ { \sec }^{2}y - 1 } = \frac{ { \sin}^{2} y}{ { \tan }^{2} y} = \frac{ { \sin }^{2}y }{ \frac{ { \sin}^{2} y}{ { \cos}^{2}y } } = { \cos }^{2} y$