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4 years ago

Is Montana of 300 better than polo g?

Mathematics

1 answer:

dezoksy [38]4 years ago

4 0

Answer

polo g is amazing

Step-by-step explanation:

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Cylinder and a cone have the same diameter: 8 inches. The height of the cylinder is 5 inches. The height of the cone is 15 inche

ss7ja [257]

Answer:

$V_{cylinder}=251.2\ in^3,$

$V_{cone}=251.2\ in^3,$

$V_{cylinder}=V_{cone}.$

Step-by-step explanation:

The volume of the cylinder is

$V_{cylinder}=\pi r^2 h,$

where r is the radius of a base circle and h is the cylinder's height.

If cylinder has diameter of 8 inches, then its radius is 4 inches. The height of the cylinder is 5 inches. Thus, the volume of the cylinder is

$V_{cylinder}=3.14\cdot 4^2\cdot 5=251.2\ in^3.$

The volume of the cone is

$V_{cone}=\dfrac{1}{3}\pi r^2 h,$

where r is the radius of a base circle and h is the cone's height.

If cone has diameter of 8 inches, then its radius is 4 inches. The height of the cone is 15 inches. Thus, the volume of the cone is

$V_{cylinder}=\dfrac{1}{3}\cdot 3.14\cdot 4^2\cdot 15=251.2\ in^3.$

As you can see the cylinder and the cone have the same volume.

4 0

4 years ago

Evaluate the expression when x = 3 and y = 5 6y/x

kondaur [170]

If x=3 and y=5 then you just substitute.
6(5)/3
30/3
=10
10 is your answer.

5 0

3 years ago

Read 2 more answers

8 people want to share a large pizza.Use a ratio to express how many pieces each person gets if the pizza is divided equally

jenyasd209 [6]

Answer:

1/8

Step-by-step explanation:

6 0

3 years ago

Miguel rented a truck for one day. There was a base fee of $20.95, and there was an additional charge of 83 cents for each mile

goblinko [34]

Answer:

254 miles

Step-by-step explanation:

7 0

3 years ago

1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t

natta225 [31]

The area of the surface given by $\vec r_1(u,v)$ is 1. In terms of a surface integral, we have

$1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

By multiplying each component in $\vec r_1$ by 5, we have

$\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}$

and the same goes for the derivative with respect to $v$ . Then the area of the surface given by $\vec r_2(u,v)$ is

$\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}$

8 0

3 years ago