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polet [3.4K]
4 years ago
7

Which situation could be modeled by using a linear function?

Mathematics
1 answer:
Snowcat [4.5K]4 years ago
8 0
(3) the cost of cell phone service that charges a base amount plus
<span>20 cents per minute</span>
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144% of what is 99 ?
Ahat [919]
After guessing and checking, the answer is around 68.8. You can use this problem to find the answer in much more reliable ways as well.
8 0
3 years ago
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PLEASE HELP ILL GIVE BRAINLIEST <br><br>​
Cloud [144]

Answer:

6 and 7

Step-by-step explanation:

3 0
2 years ago
write a number you know that is greater than 1 scientific notation.Explain how you know it is greater than 1
netineya [11]

Answer:

hhgvvhjhcffffhh

Step-by-step explanation:

tfffffffgfddvvgggg

6 0
3 years ago
A city council organized a marathon race to promote good health. There were 3 times as many female participants as male particip
hichkok12 [17]

Answer:

609 males

Step-by-step explanation:

A city council organized a marathon race to promote good health.

Let the number of

Females = x

Males = y

There were 3 times as many female participants as male participants in the marathon.

3x = y

If the total number of participants was 812,

x + y = 812..... Equation 1

We substitute 3x for y in Equation 1

x + 3x = 812

4x = 812

x= 812/4

x = 203 females

3x = y

Solving for y

3(203) = 609 males

The number of males participants = 609

5 0
3 years ago
A couple plans to have three children. Each child is equally likely to be a girl or​ boy, with gender independent of that of the
wlad13 [49]

Answer:

a) X={BBB;BBG:BGG:GGG}

b) P(BBB)=0.125

c) P(BBB)=0.133

Step-by-step explanation:

The sample space states all the possible values that the random variable can take. In this case, the order does not matter, so the possible combinations for the random variable are:

X={BBB;BBG:BGG:GGG}

The probability p of having a boy is p=0.5, as it is equally likely to have a girl or a boy.

The probability that all 3 children are boys can be calculated multiplying 3 times the probability of having a boy. That is:

P(X=BBB)=p\cdot p\cdot \cdot p =p^3=0.5^3=0.125

In the case that the chance of having a boy is p'=0.51, the probabiltity of having 3 boys become:

P(X=BBB)=p'^3=0.51^3=0.133

3 0
3 years ago
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