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kompoz [17]
3 years ago
8

Please help ASAP! Use (f/g)x f(x)=6x^2+36 g(x)=6x^2+34x-12 Show your work please!

Mathematics
1 answer:
olga55 [171]3 years ago
5 0

Answer:

\frac{3}{3x-1}

Step-by-step explanation:

\frac{f(x)}{g(x)}\\\frac{6x^2+36}{6x^2+34x-12}\\\frac{6(x^2+6)}{2(3x^2+17x-6)}Factor out a 6 from the numerator and 2 from the denominator

\frac{3(x^2+6)}{3x^2+17x-6} 2 in the denominator divides the 6 in the numerator

\frac{3(x+6)}{(3x-1)(x+6)} factor the denominator, let me know if you need help with this

\frac{3}{3x-1} the (x+6)s cancel

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