Question

Please help ASAP! Use (f/g)x f(x)=6x^2+36 g(x)=6x^2+34x-12 Show your work please!

Answer 1

Answer:

$\frac{3}{3x-1}$

Step-by-step explanation:

$\frac{f(x)}{g(x)}\\\frac{6x^2+36}{6x^2+34x-12}\\\frac{6(x^2+6)}{2(3x^2+17x-6)}$Factor out a 6 from the numerator and 2 from the denominator

$\frac{3(x^2+6)}{3x^2+17x-6}$ 2 in the denominator divides the 6 in the numerator

$\frac{3(x+6)}{(3x-1)(x+6)}$ factor the denominator, let me know if you need help with this

$\frac{3}{3x-1}$ the (x+6)s cancel