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2 years ago

What is the distance between the solutions to the quadratic equation x2 – 7x + 10 = 28

Mathematics

1 answer:

Kryger [21]2 years ago

4 0

Answer:

Step-by-step explanation:

Given

x² - 7x + 10 = 28 ( subtract 28 from both sides )

x² - 7x - 18 = 0 ← in standard form

(x - 9)(x + 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 9 = 0 ⇒ x = 9

x + 2 = 0 ⇒ x = - 2

The distance between the solutions is

| 9 - (- 2) | = | 11 = 11 units

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Answer:

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Step-by-step explanation:

we know that

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Let

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the formula to calculate the distance between two points is equal to

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substitute in the formula

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$d=\sqrt{(0)^{2}+(-13)^{2}}$

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substitute in the formula

$d=\sqrt{(6-1)^{2}+(10+6)^{2}}$

$d=\sqrt{(5)^{2}+(16)^{2}}$

$dBC=16.8\ units$

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substitute in the formula

$d=\sqrt{(6-1)^{2}+(10-7)^{2}}$

$d=\sqrt{(5)^{2}+(3)^{2}}$

$dAC=5.8\ units$

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$P=dAB+dBC+dAC$

$P=13+16.8+5.8=35.6\ units$

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