If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
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Ratio Given
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Apple : Strawberry
4 : 5
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Find difference in parts
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5 - 4 = 1
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Find Number of strawberry cakes
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1 part = 24 cakes
5 parts = 24 x 5 = 120
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Find number of apple cakes
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1 part = 24 cakes
4 parts = 24 x 4 = 96
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Total number of cakes
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120 + 96 + 144 = 360
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Percentage of cranberry cakes
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144/360 x 100 = 40%
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Answer: 40% of the cakes are cranberry cakes
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Answer:
Number of drink = 5
Number of pretzel = 9
Step-by-step explanation:
Given:
Cost of each drink = $4
Cost of each pretzel = $5
Total money = 65
Total number of drink and pretzel = 14
Find:
Number of drink and pretzel
Computation:
Number of drink = x
Number of pretzel = 14 - x
So,
x(4) + (14-x)5 = 65
4x + 70 - 5x = 65
x = 5
Number of drink = 5
Number of pretzel = 14 - x
Number of pretzel = 14 - 5 = 9