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LuckyWell [14K]
2 years ago
10

Clayton and Olivia played a computer game.Olivia final score was 2306421 and Clayton was 2302972.show these numbers on a number

line.whose score was greater?how do you know?
Mathematics
1 answer:
Elden [556K]2 years ago
3 0
(I cannot be the number line bit sorry)
When you're finding which one is greater, you can either write these out in words, or you can put them next to eachother.
In words- Olivia: Two million, three hundred and six thousand, four hundred and twenty one. (2306421)
Clayton- Two million, three hundred and two thousand, nine hundred and seventy two. (2302972)

From writing them out, you can see that Olivia's score has 'three hundred and six thousands', where as, Clayton has 'three hundred and two thousand'

Therefore, Olivia got the higher score.
Hope this helps :) 
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<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

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<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

First=10a^{2}

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We have that the coefficients of the quadratic terms that can be obtained by squaring are:

16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}

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So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

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