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Degger [83]
3 years ago
5

Which expression represents the factored form of 6x^{2}-13x-5?

Mathematics
1 answer:
Leni [432]3 years ago
7 0

Answer:(2x - 5)(3x + 1)

Step-by-step explanation:

6x^2 - 13x - 5

6x^2 + 2x - 15x - 5

2x (3x + 1) - 5 (3x + 1)

(2x - 5)(3x + 1)

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Put these over a common denominator: ³/5 and 4/7
Anastaziya [24]

ANSWER 35

Step-by-step explanation:

7 and 5 - 35

Now just simplify the 3 and 4 :)

6 0
3 years ago
The sum of Jack and Jill's ages is 84. If Jill is twenty times
9966 [12]

Answer:

4.2

Step-by-step explanation:

84 divided by 20  4.2

7 0
3 years ago
How do you Multiply the polynomials
Mekhanik [1.2K]

Answer:

Multiply by every term in the second expression:

Multiply by every term in the second expression.

Multiply 1 by every term in the second expression.

Now we take those nine terms (everything on the right side of those above equations) and add 'em all up


4 0
3 years ago
In one​ community, a random sample of 26 foreclosed homes sold for an average of ​$443 comma 555 with a standard deviation of ​$
alexandr1967 [171]

Answer:

i) a) Normality : We assume that the data follows approximately a normal distribution

ii) Random sample: The data comes from a random sample

iii) The sample size represent <10% of the population size

We assume that all the conditions are satisfied for this case.

b) 443555-2.06\frac{195381}{\sqrt{26}}=364621.22    

443555+2.06\frac{195381}{\sqrt{26}}=522488.775    

So on this case the 95% confidence interval would be given by (364621.22;522488.775)    

c) We are confident at 95% that the true mean of foreclosed homes sold's are between (364621.22;522488.775)    

d) Since the lower value for the 95% confidence interval is higher than 300000 we can conclude that yes differes significantly and the true mean is different from 300000 at 5% of significance.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=443555 represent the sample mean

\mu population mean (variable of interest)

s=195381 represent the sample standard deviation

n=26 represent the sample size  

Part a

We need some conditions:

a) Normality : We assume that the data follows approximately a normal distribution

b) Random sample: The data comes from a random sample

c) The sample size represent <10% of the population size

We assume that all the conditions are satisfied for this case.

Part b

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=26-1=25

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,25)".And we see that t_{\alpha/2}=2.06

Now we have everything in order to replace into formula (1):

443555-2.06\frac{195381}{\sqrt{26}}=364621.22    

443555+2.06\frac{195381}{\sqrt{26}}=522488.775    

So on this case the 95% confidence interval would be given by (364621.22;522488.775)    

Part c

We are confident at 95% that the true mean of foreclosed homes sold's are between (364621.22;522488.775)    

Part d

Since the lower value for the 95% confidence interval is higher than 300000 we can conclude that yes differes significantly and the true mean is different from 300000 at 5% of significance.

8 0
3 years ago
Find the mean of the integers.<br><br> −54,−32,−70,−25,−65,−42
lisov135 [29]

Answer:

-48

Step-by-step explanation:

Mean means to find the average.  Add all the numbers and divide by the amount of numbers there are, in this case.

7 0
3 years ago
Read 2 more answers
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