Question

The coordinates of the vertices of △JKL are J(0, 2) , K(3, 1) , and L(1, −5) .

Answer 1

-1/3
3
-7
Is
Two have the product of -1

Answer 2

we know that

If two lines are perpendicular, then the product of their slopes is equal to minus one

so

$m1*m2=-1$

we have

$J(0,2)\\K(3,1)\\L(1,-5)$

Remember that

the formula to calculate the slope between two points is equal to

$m=\frac{(y2-y1)}{(x2-x1)}$

Step 1

Find the slope JK

we have

$J(0,2)\\K(3,1)$

substitute in the slope's formula

$m=\frac{(1-2)}{(3-0)}$

$m=\frac{(-1)}{(3)}$

$mJK=-\frac{1}{3}$

Step 2

Find the slope KL

we have

$K(3,1)\\L(1,-5)$

substitute in the slope's formula

$m=\frac{(-5-1)}{(1-3)}$

$m=\frac{(-6)}{(-2)}$

$mKL=3$

Step 3

Find the slope JL

we have

$J(0,2)\\L(1,-5)$

substitute in the slope's formula

$m=\frac{(-5-2)}{(1-0)}$

$m=\frac{(-7)}{(1)}$

$mJL=-7/tex]Step 4Verify if the sides of the triangle are perpendicularMultiply the slopesJK and KL[tex]mJK=-\frac{1}{3}$    

$mKL=3$

$-\frac{1}{3}*3=-1$ ------> sides JK and KL are perpendicular

when verifying that it has two perpendicular sides, it is not necessary to continue verifying the others, since a triangle can only have a single right angle

therefore

the answer in the attached figure