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Fed [463]
2 years ago
8

Find the angle between the given vector in degrees. u=<6, 4>, v=<7, 5> HELPPPPPPPPPP

Mathematics
1 answer:
Paladinen [302]2 years ago
7 0

Recall that

\vec a\cdot\vec b=\|\vec a\|\|\vec b\|\cos\theta

where \theta is the angle between the vectors \vec a,\vec b whose magnitudes are \|\vec a\|,\|\vec b\|, respectively.

We have

\langle6,4\rangle\cdot\langle7,5\rangle=\sqrt{6^2+4^2}\sqrt{7^2+5^2}\cos\theta

\cos\theta=\dfrac{31}{\sqrt{962}}\implies\theta\approx88.2^\circ

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Which of the following best describes the equation below? y=-6x+7
Hitman42 [59]

Answer:

y=-6x+7    (Negative Slope)

Step-by-step explanation:

This equation is in slope intercept form.

7= y-intercept

-6= slope

This means that when you plot this on a graph, your slope will be negative.

5 0
3 years ago
The ratio of boys to girl at the dance was 9 to 5.how many girls were at the dance if there were 85 girls ar the dance
liq [111]

Answer:

153

Step-by-step explanation:

ans.

5x=85

x =85÷5

=17

9x=17x9

=153

6 0
3 years ago
Find the set below using A=(5,6,9), and so on (Explanation is in picture)
anzhelika [568]

The result is: {5,6,9}

Step-by-step explanation:

Given

U = {0,1,2,......,10}

A = {5,6,9}

B = {0, 6, 7, 10}

We have to find

(A∩B)U(A∩B')

First of all,

<u>B':</u>

B' = U -B = {0,1,2,......,10} -  {0, 6, 7, 10}

= {1,2,3,4,5,8,9}

<u>A∩B':</u>

A∩B' = {5,6,9} ∩ {1,2,3,4,5,8,9}

= {5,9}

<u>A∩B:</u>

A∩B = {5,6,9} ∩ {0, 6, 7, 10}

={6}

At the end we have to find union

(A∩B)U(A∩B') = {6} U {5,9}

(A∩B)U(A∩B') = {5,6,9}

Hence,

The result is: {5,6,9}

Keywords: Sets , Union

Learn more about sets at:

  • brainly.com/question/3126500
  • brainly.com/question/3306327

#LearnwithBrainly

8 0
3 years ago
Help pls<br> ssssssssssssssssssssssssssssss
kirza4 [7]

Answer:

The numbers , -0.82 , -1/5 , and -4/5 are closest to - 1

The number, -0.28 is the ONLY number closest to - 1/4

hope this helps

8 0
3 years ago
What is the value of x in this simplified expression
arsen [322]

Answer:

7

Step-by-step explanation:

  • (-j)^-7 = 1/(-j)^x

Changing LHS as

  • 1/(-j)^7 = 1/(-j)^x

Comparing LHS and RHS

  • x = 7
8 0
3 years ago
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